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Brut [27]
2 years ago
8

Su una strada rettilinea ci sono due semafori che distano 98 m e che diventano verdi contemporaneamente. Dal primo semaforo part

e un’auto che sì muove alla velocità costante di 43 km/h; dall’altro semaforo parte, nel verso opposto, un camper che viaggia alla velocità costante di 36 km/h.
Determina quanto tempo dopo l'accensione del verde i due automezzi sì affiancano e quanta strada ha percorso l'automobile in quel momento.
Physics
1 answer:
pantera1 [17]2 years ago
3 0

Answer:

Le due rette rappresentano le leggi del moto di due punti

materiali (per esempio due macchine) che si muovono di moto

rettilineo uniforme. La retta meno pendente (velocità più bassa)

è riferita alla macchina che parte da una posizione iniziale più

avanti rispetto alla seconda macchina. Però, la seconda

macchina, avendo una velocità maggiore della prima (retta più

pendente), nonostante parta più indietro rispetto alla prima, dopo

un certo tempo la raggiungerà. Pertanto, il punto P, intersezione

delle due rette, rappresenta la situazione fisica in cui la seconda

macchina raggiunge la prima. In particolare, le coordinate del

punto P (tempo e spazio), rappresentano l’istante e la posizione

in cui la seconda macchina raggiunge la prima.

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What part of this transverse wave is the green arrow identifying?<br><br> Help plz
cupoosta [38]

It is the 'crest' part that the green arrow is identifying.

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3 years ago
On the earth, when an astronaut throws a 0.250-kg stone vertically upward, it returns to his hand a time T later. On planet X he
Liula [17]

Answer:

correct is d) a ’= g / 2

Explanation:

For this exercise let's use the kinematics equations

On earth

      v = v₀ - a t

     a = (v₀- v) / T

On planet X

    v = v₀ - a' t’

    a ’= (v₀-v) / 2T

Let's substitute the land values ​​in plot X

     a’= a / 2

Now let's use Newton's second law

       W = ma

      m g = m a

      a = g

We substitute

      a ’= g / 2

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4 0
3 years ago
A person jumps out a fourth-story window 14 m above a firefighter safety net. The survivor stretches the net 1.8 m before coming
Monica [59]

Answer:

The deceleration is  a =  - 76.27 m/s^2

Explanation:

From the question we are told that

   The height above  firefighter safety net is H  = 14 \ m

   The length by which the net is stretched is s =  1.8 \ m

   

From the law of energy conservation

    KE_T + PE_T =  KE_B + PE_B

 Where KE_T is the kinetic energy of the person before jumping which equal to zero(because to kinetic energy at maximum height )

   and  PE_T is the potential energy of the before jumping  which is mathematically represented at

          PE_T  = mg H

and  KE_B is the kinetic energy of the person just before landing on the safety net  which is mathematically represented at

        KE_B = \frac{1}{2} m v^2

and  PE_B is the potential energy of the person as he lands on the safety net which has a value of zero (because it is converted to kinetic energy )

   So the above equation becomes

          mgH =  \frac{1}{2} m v^2

=>           v =  \sqrt{2 gH }

    substituting values

                v =  16.57 m/s

Applying the equation o motion

             v_f =  v  + 2 a s

Now the final velocity is zero because the person comes to rest

      So

         0 = 16.57 + 2 * a * 1.8

            a =  - \frac{16.57^2 }{2 * 1.8}

            a =  - 76.27 m/s^2

         

         

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According to x-ray observations, the space between galaxies in a galaxy cluster is?
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Heating also occurs as galaxies expel out most of the gas that fell into them. The final product is a warm/hot phase, with temperatures of > 10^{5} K.

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