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Brut [27]
2 years ago
8

Su una strada rettilinea ci sono due semafori che distano 98 m e che diventano verdi contemporaneamente. Dal primo semaforo part

e un’auto che sì muove alla velocità costante di 43 km/h; dall’altro semaforo parte, nel verso opposto, un camper che viaggia alla velocità costante di 36 km/h.
Determina quanto tempo dopo l'accensione del verde i due automezzi sì affiancano e quanta strada ha percorso l'automobile in quel momento.
Physics
1 answer:
pantera1 [17]2 years ago
3 0

Answer:

Le due rette rappresentano le leggi del moto di due punti

materiali (per esempio due macchine) che si muovono di moto

rettilineo uniforme. La retta meno pendente (velocità più bassa)

è riferita alla macchina che parte da una posizione iniziale più

avanti rispetto alla seconda macchina. Però, la seconda

macchina, avendo una velocità maggiore della prima (retta più

pendente), nonostante parta più indietro rispetto alla prima, dopo

un certo tempo la raggiungerà. Pertanto, il punto P, intersezione

delle due rette, rappresenta la situazione fisica in cui la seconda

macchina raggiunge la prima. In particolare, le coordinate del

punto P (tempo e spazio), rappresentano l’istante e la posizione

in cui la seconda macchina raggiunge la prima.

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?do you have a picture of the options orr ?

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Identify the type of electrification of the road
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3 years ago
Observe yourself breathing and count the number of times you inhale per second. During each breath you probably inhale 0.66 L of
Pavel [41]

To solve this exercise it is necessary to apply the concepts related to Robert Boyle's law where:

PV=nRT

Where,

P = Pressure

V = Volume

T = Temperature

n = amount of substance

R = Ideal gas constant

We start by calculating the volume of inhaled O_2 for it:

V = 21\% * 0.66L

V = 0.1386L

Our values are given as

P = 1atm

T=293K R = 0.083145kJ*mol^{-1}K^{-1}

Using the equation to find n, we have:

PV=nRT

n = \frac{PV}{RT}

n = \frac{(1)(0.1386)}{(0.0821)(293)}

n = 5.761*10^{-3}mol

Number of molecules would be found through Avogadro number, then

\#Molecules = 5.761*10^{-3}*6.022*10^{23}

\#Molecules = 3.469*10^{21} molecules

7 0
3 years ago
A point charge Q is held at a distance r from the center of a dipole that consists of two charges ±q separated by a distance s.
marishachu [46]

Answer:

a) the magnitude of the force is

F= Q(\frac{kqs}{r^3}) and where k = 1/4πε₀

F = Qqs/4πε₀r³

b)  the magnitude of the torque on the dipole

τ = Qqs/4πε₀r²

Explanation:

from coulomb's law

E = \frac{kq}{r^{2} }

where k = 1/4πε₀

the expression of the electric field due to dipole at a distance r is

E(r) = \frac{kp}{r^{3} } , where p = q × s

E(r) = \frac{kqs}{r^{3} } where r>>s

a) find the magnitude of force due to the dipole

F=QE

F= Q(\frac{kqs}{r^3})

where k = 1/4πε₀

F = Qqs/4πε₀r³

b) b) magnitude of the torque(τ) on the dipole is dependent on the perpendicular forces

τ = F sinθ × s

θ = 90°

note: sin90° = 1

τ = F × r

recall  F = Qqs/4πε₀r³

∴ τ = (Qqs/4πε₀r³) × r

τ = Qqs/4πε₀r²

8 0
3 years ago
A 18.0-kg rock is sliding on a rough, horizontal surface at 7.10 m/s and eventually stops due to friction. the coefficient of ki
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A = .3*g = 2.94 m/s² 

<span>t = v/a = 9/2.94 = 3.061 sec </span>

<span>W = E/t = ½mv²/t = ½*40*9²/3.061 = 529.2 watts</span>
4 0
3 years ago
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