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Brut [27]
2 years ago
8

Su una strada rettilinea ci sono due semafori che distano 98 m e che diventano verdi contemporaneamente. Dal primo semaforo part

e un’auto che sì muove alla velocità costante di 43 km/h; dall’altro semaforo parte, nel verso opposto, un camper che viaggia alla velocità costante di 36 km/h.
Determina quanto tempo dopo l'accensione del verde i due automezzi sì affiancano e quanta strada ha percorso l'automobile in quel momento.
Physics
1 answer:
pantera1 [17]2 years ago
3 0

Answer:

Le due rette rappresentano le leggi del moto di due punti

materiali (per esempio due macchine) che si muovono di moto

rettilineo uniforme. La retta meno pendente (velocità più bassa)

è riferita alla macchina che parte da una posizione iniziale più

avanti rispetto alla seconda macchina. Però, la seconda

macchina, avendo una velocità maggiore della prima (retta più

pendente), nonostante parta più indietro rispetto alla prima, dopo

un certo tempo la raggiungerà. Pertanto, il punto P, intersezione

delle due rette, rappresenta la situazione fisica in cui la seconda

macchina raggiunge la prima. In particolare, le coordinate del

punto P (tempo e spazio), rappresentano l’istante e la posizione

in cui la seconda macchina raggiunge la prima.

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2 years ago
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zubka84 [21]

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Explanation:

Hope this helps!

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3 years ago
There is a 50 g sample of Ra-229. It has a half-life of 4 minutes.
Sloan [31]

Via half-life equation we have:


A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h} }


Where the initial amount is 50 grams, half-life is 4 minutes, and time elapsed is 12 minutes.  By plugging those values in we get:

A_{final}=50(\frac{1}{2})^\frac{12}{4}=50(\frac{1}{2})^{3}=50(\frac{1}{8})=6.25g


There is 6.25 grams left of Ra-229 after 12 minutes.

4 0
3 years ago
A 24 kg crate is moving at a constant speed because it is being pushed with a force of 53n. What would be the coefficient of kin
____ [38]

Answer:

The coefficient of kinetic friction between the crate and the floor can be calculated using the formula μ = Ff / N, where Ff is the frictional force, N is the normal force, and μ is the coefficient of kinetic friction.

In this case, the normal force is equal to the weight of the crate, which is 24 kg * 9.8 m/s2 = 235.2 N. The frictional force can be calculated using the formula Ff = μ * N, where μ is the coefficient of kinetic friction and N is the normal force.

If we substitute the values for N and Ff into the formula for the coefficient of kinetic friction, we get:μ = 53 N / 235.2 N = 0.225

Therefore, the coefficient of kinetic friction between the crate and the floor is 0.225.

6 0
11 months ago
If we warm a volume of air, it expands. Does it then follow that if we expand a volume of air, it warms? Explain.
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3 0
2 years ago
Read 2 more answers
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