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2 years ago

A physical quantity, G, is defined by G = (Original mass x time)/(change in mass), what is the S.I. unit of G ?

1 answer:

4 0

The gravitational constant (G) in its base SI units is

3/2
m
3
k
g
/
s
2

But is often seen written as

⋅
N
⋅
2/2
m
2
/
k
g
2

Where N is the Newton unit. N=kg ⋅
⋅
m/s 2
2

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2 (a) A plane from airport A flies 280 km to the east to airport B. The plane then travelled north to airport C, 190 km away. (i

Mekhanik [1.2K]

Answer:

See below

Explanation:

See attached diagram

280 km east then 190 km north

Use Pythagorean theorem to find the resultant displacement

d^2 = 280^2 + 190^2

d = 338.4 km

Angle will be arctan ( 190/280) = 34.16 °

4 0

2 years ago

A spherical asteroid of average density would have a mass of 8.7×1013kg if its radius were 2.0 km. 1. If you and your spacesuit

Law Incorporation [45]

1. 0.16 N

The weight of a man on the surface of asteroid is equal to the gravitational force exerted on the man:

$F=G\frac{Mm}{r^2}$

where

G is the gravitational constant

$M=8.7\cdot 10^{13}kg$ is the mass of the asteroid

m = 100 kg is the mass of the man

r = 2.0 km = 2000 m is the distance of the man from the centre of the asteroid

Substituting, we find

$F=(6.67\cdot 10^{-11}m^3 kg^{-1} s^{-2})\frac{(8.7\cdot 10^{13} kg)(110 kg)}{(2000 m)^2}=0.16 N$

2. 1.7 m/s

In order to stay in orbit just above the surface of the asteroid (so, at a distance r=2000 m from its centre), the gravitational force must be equal to the centripetal force

$m\frac{v^2}{r}=G\frac{Mm}{r^2}$

where v is the minimum speed required to stay in orbit.

Re-arranging the equation and solving for v, we find:

$v=\sqrt{\frac{GM}{r}}=\sqrt{\frac{(6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2})(8.7\cdot 10^{13} kg)}{2000 m}}=1.7 m/s$

3 0

4 years ago

the two rotating systems shown in the figure differ only in that the two identical movable masses are positioned at different di

svetoff [14.1K]

Answer: the block at the right lands first

Explanation:

7 0

3 years ago

Question 9 of 10

mixer [17]

Answer:

I believe the correct answer is B..<u>" 1 "</u>

Explanation:

hope it helps! ;)

8 0

3 years ago

An astronaut sings a song upon arriving on Planet Mongo. When her vocal cord produces an oscillation at 600 Hertz, she detects t

Paraphin [41]

The speed of sound on planet is 210 m/s.

<h3>What is Oscillation?</h3>

Oscillation is the repeating or periodic change of a quantity around a central value or between two or more states, often in time. Alternating current and a swinging pendulum are two common examples of oscillation.

There are 3 main types of Oscillation –

Free
damped
forced oscillation

f = frequency = 600 Hz

lambda = wavelength = 35 cm = 0.35 m

Now,

V = speed = f × lambda = 210 m/s

Hence, speed of sound on planet is 210 m/s.

to learn more about oscillation go to -

brainly.com/question/12622728

#SPJ4

3 0

2 years ago