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mafiozo [28]
2 years ago
6

A physical quantity, G, is defined by G = (Original mass x time)/(change in mass), what is the S.I. unit of G ?

Physics
1 answer:
Andrei [34K]2 years ago
4 0
The gravitational constant (G) in its base SI units is

3/2
m
3
k
g
/
s
2


But is often seen written as

⋅
N
⋅
2/2
m
2
/
k
g
2


Where N is the Newton unit. N=kg ⋅
⋅
m/s 2
2


You might be interested in
Which example best demonstrates how unbalanced forces change the speed of an object's motion?
exis [7]

I don’t see a picture but unbalanced forces could be two boys pushing with a combined force of 400 Newton’s but the surface of what the box is laying on being 600 meaning since the ground is creating a higher force in the form of friction it will slow the boys down. When forces are unbalanced it means that the object can not be still or moving at a constant speed  when one force is greater by a significant amount the object either slows quickly or accelerates fast depending on which factor is greater.

4 0
2 years ago
An object accelerates from rest and travels 53 m west in 5.2 s. Determine the acceleration
zmey [24]

Answer:

20.4m/s²

Explanation:

Given parameters:

Initial velocity  = 0m/s

Distance  = 53m

Time  = 5.2s

Unknown:

Acceleration  = ?

Solution:

This is a linear motion and we use the right motion equation;

        S = ut  + \frac{1}{2}at²

S is the distance

u is the initial velocity

a is the acceleration

t is the time

 Insert the parameters and solve;

       53  = (0x 5.2) +  \frac{1}{2} x a x 5.2

       53  = 2.6a

         a = \frac{53}{2.6}  = 20.4m/s²

6 0
2 years ago
1. Indica cuáles son los reactivos y productos de la reacción química representada por la ecuación siguiente, y señala en que es
bearhunter [10]

Answer:

Los reactivos, con su correspondiente estado de agregación, son:

  • Mg: estado sólido
  • HCl: estado acuoso

Los productos, con su correspondiente estado de agregación, son:

  • MgCl₂: estado acuoso
  • H₂: estado gaseoso

Explanation:

Una reacción química es un proceso por el cual una o más sustancias se transforman en otra u otras sustancias con propiedades diferentes. En otras palabras, las reacciones químicas son procesos en los que los átomos rompen sus enlaces químicos y forman otros nuevos, cambiando la naturaleza de las sustancias que intervienen.

En una ecuación química se representan dos términos. En el primero, el de la  derecha, se escriben los reactivos, expresados mediante sus fórmulas químicas  correspondientes y separados por un signo más. Por otro lado, el término de la izquierda, en  el que aparecen los productos, también representados por sus formulas químicas  correspondientes y con signos más entre ellos. Entre ambos términos suele ponerse  una flecha que indica que se ha producido la reacción química correspondiente.

Las sustancias que hay antes de producirse el cambio y que desaparecen se llaman reactivos. Las sustancias que hay después de producirse el cambio y que aparecen o se generan se llaman productos.

El estado de agregación en una reacción química se indica poniendo detrás del nombre o la fórmula de la sustancia y entre paréntesis la notación siguiente:

  • Sustancias sólidas (s)
  • Sustancias líquidas (l)
  • Sustancias gaseosas (g)
  • Sustancias disueltas en agua (aq)

En este caso tienes la reacción química:

Mg (s) + 2 HCl (aq) -> MgCl₂ (aq) + H₂ (g)

Entonces, <u><em>en este caso los reactivos, con su correspondiente estado de agregación, son:</em></u>

  • <u><em>Mg: estado sólido</em></u>
  • <u><em>HCl: estado acuoso</em></u>

<u><em>Por otro lado, los productos, con su correspondiente estado de agregación, son:</em></u>

  • <u><em>MgCl₂: estado acuoso</em></u>
  • <u><em>H₂: estado gaseoso</em></u>

6 0
2 years ago
1. A small light bulb is shining light on a basketball (diameter is 23 cm or 9 inches). The light bulb is 3 m from the closest s
siniylev [52]

Answer:

The size (diameter) of the basketball's shadow on the wall is approximately 53.38 cm

Explanation:

The given parameters of the basketball are;

The diameter of the basketball = 23 cm (9 inches)

The distance of the light bulb from the closest side of the basketball = 3 m

The distance from the ball to the wall = 4 m

The distance from the light source to the center of the ball, d = 3 m + 0.23/2 m = 3.115 m

The angle the light ray makes with the edge of the ball, θ = arctan(0.115/3.115)

Therefore, the ratio of the shadow width divided by 2 to the distance from the light from the wall = 0.115/3.115

The distance from the light from the wall = 3 m + 4 m + 0.23 m = 7.23 m

Therefore;

((The width of the shadow)/2)/(The distance from the light from the wall) = 0.115/3.115

∴ ((The width of the shadow)/2)/(7.23 m) = 0.115/3.115

((The width of the shadow)/2) = 7.23 m × 0.115/3.115 = 16629/62300 m ≈ 0.2669 m = 26.69 cm

The width (diameter) of the shadow on the wall = 2 × 16629/62300 m ≈ 0.5338 m = 53.38 cm

The size (diameter) of the basketball's shadow on the wall ≈ 53.38 cm

4 0
2 years ago
A 81 kg person sits on a 3.8 kg chair. Each leg of the chair makes contact with the floor in a circle that is 1.2 cm in diameter
tankabanditka [31]

Answer:

1.9 MPa

Explanation:

Mass of person = 81 kg

Mass of chair = 3.8 kg

Diameter of contact point = 1.2 cm = D

Radius of contact point = 1.2/2 = 0.6 cm

Total mass of chair and person = 81 + 3.8 = 84.8 kg = M

Acceleration due to gravity = 9.81 m/s²

Force acting on the floor

<em>F = Mg</em>

<em>⇒F = 84.8×9.81</em>

<em>⇒F = 831.888 N</em>

Area of the contact point

<em>A = πR²</em>

<em>⇒A = π0.006²</em>

<em>⇒A = π0.000036 m²</em>

Area of the four points is

<em>4A = 0.000144π m²</em>

Pressure

p=\frac{F}{A}\\\Rightarrow p=\frac{831.888}{0.000144\pi}\\\Rightarrow p=1838876.21\ Pa=1.83887621\times 10^6\ Pa=1.9 MPa

Pressure exerted on the floor by each leg of the chair is 1.9 MPa

5 0
3 years ago
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