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mafiozo [28]
2 years ago
6

A physical quantity, G, is defined by G = (Original mass x time)/(change in mass), what is the S.I. unit of G ?

Physics
1 answer:
Andrei [34K]2 years ago
4 0
The gravitational constant (G) in its base SI units is

3/2
m
3
k
g
/
s
2


But is often seen written as

⋅
N
⋅
2/2
m
2
/
k
g
2


Where N is the Newton unit. N=kg ⋅
⋅
m/s 2
2


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You're out for run. Your initial velocity is 1.5 m/s. Suddenly a crazy dog starts chasing you and you accelerate to a velocity o
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The displacement of your motion during the entire motion is 22.5 m

The given parameters;

  • your initial velocity, u = 1.5 m/s
  • your final velocity , v = 3 m/s
  • time of motion, t = 10 s

The displacement of your motion during the entire motion is calculated from your average velocity and time of motion.

This magnitude of this <em>displacement</em> is calculated  as follows;

s = (\frac{u+ v}{2} )t\\\\s = (\frac{1.5 + 3}{2} ) \times 10\\\\s = 22.5 \ m

Thus, the displacement of your motion during the entire motion is 22.5 m.

Learn more here: brainly.com/question/17345815

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A.Whale communication. Blue whales apparently communicate with each other using sound of frequency 17.0 Hz, which can be heard n
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A. 90.1 m

The wavelength of a wave is given by:

\lambda=\frac{v}{f}

where

v is the speed of the wave

f is its frequency

For the sound emitted by the whale, v = 1531 m/s and f = 17.0 Hz, so the wavelength is

\lambda=\frac{1531 m/s}{17.0 Hz}=90.1 m

B. 102 kHz

We can re-arrange the same equation used previously to solve for the frequency, f:

f=\frac{v}{\lambda}

where for the dolphin:

v = 1531 m/s is the wave speed

\lambda=1.50 cm=0.015 m is the wavelength

Substituting into the equation,

f=\frac{1531 m/s}{0.015 m}=1.02 \cdot 10^5 Hz=102 kHz

C. 13.6 m

Again, the wavelength is given by:

\lambda=\frac{v}{f}

where

v = 340 m/s is the speed of sound in air

f = 25.0 Hz is the frequency of the whistle

Substituting into the equation,

\lambda=\frac{340 m/s}{25.0 Hz}=13.6 m

D. 4.4-8.7 m

Using again the same formula, and using again the speed of sound in air (v=340 m/s), we have:

- Wavelength corresponding to the minimum frequency (f=39.0 Hz):

\lambda=\frac{340 m/s}{39.0 Hz}=8.7 m

- Wavelength corresponding to the maximum frequency (f=78.0 Hz):

\lambda=\frac{340 m/s}{78.0 Hz}=4.4 m

So the range of wavelength is 4.4-8.7 m.

E. 6.2 MHz

In order to have a sharp image, the wavelength of the ultrasound must be 1/4 of the size of the tumor, so

\lambda=\frac{1}{4}(1.00 mm)=0.25 mm=2.5\cdot 10^{-4} m

And since the speed of the sound wave is

v = 1550 m/s

The frequency will be

f=\frac{v}{\lambda}=\frac{1550 m/s}{2.5\cdot 10^{-4} m}=6.2\cdot 10^6 Hz=6.2 MHz

3 0
3 years ago
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