Force = rate of change of momentum = 0.16(38 + 44)/0.002 = 6560 N
Answer:
The distance traveled during its acceleration, d = 214.38 m
Explanation:
Given,
The object's acceleration, a = -6.8 m/s²
The initial speed of the object, u = 54 m/s
The final speed of the object, v = 0
The acceleration of the object is given by the formula,
a = (v - u) / t m/s²
∴ t = (v - u) / a
= (0 - 54) / (-6.8)
= 7.94 s
The average velocity of the object,
V = (54 + 0)/2
= 27 m/s
The displacement of the object,
d = V x t meter
= 27 x 7.94
= 214.38 m
Hence, the distance the object traveled during that acceleration is, a = 214.38 m
F = 500N
S = 5m
T = 1.2s
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P = ?
We can use formula P = F * V, just because it was a smooth slide we can assume that average speed was V = S/T = 5 / 1.2 = 50/12
So the final answer would be:
P = F * V = 500 * 50/12
Are you sure those are correct numbers? The answer don't look nice :D
Tamam hocam nasılsınız hocam proje konularını atabilirmisiniz ne kadar çok seviyorum çok öpüyorum iyi akşamlar yarın görüşürüz iyi geceler Allah rahatlık var bir şey var ya bir insan değilim ki bir şey olmaz sen kaç gibi müsait olur musun lütfen bana yardımcı olabilir misin bir insan bir
Here's an interesting fact to remember: (Period of any wave) x (Frequency of the wave) = 1 .If you can memorize that, then you'll always remember that Period = 1 / frequencyand Frequency = 1 / period. The second one is what you need for this problem. Frequency = 1 / period = 1 / (4.85 x 10⁻² second) = 1 / (0.0485 second) =20.62 / second
=20.62 Hz. (rounded)
Explanation:(Plato) I just took the test
