Answer : The original mass of the sample was 0.581 grams.
Explanation :
Expression for rate law for first order kinetics is given by:
where,
k = rate constant = 
t = time passed by the sample = 5.00 years
a = original or initial amount of the reactant = ?
a - x = amount left after decay process = 0.302 g
Now put all the given values in above equation, we get
Therefore, the original mass of the sample was 0.581 grams.
The answer to your question is 185
Answer:
230.4 N
Explanation:
From the question given above, the following data were obtained:
Charge (q) of each protons = 1.6×10¯¹⁹ C
Distance apart (r) = 1×10¯¹⁵ m
Force (F) =?
NOTE: Electric constant (K) = 9×10⁹ Nm²/C²
The force exerted can be obtained as follow:
F = Kq₁q₂ / r²
F = 9×10⁹ × (1.6×10¯¹⁹)² / (1×10¯¹⁵)²
F = 9×10⁹ × 2.56×10¯³⁸ / 1×10¯³⁰
F = 2.304×10¯²⁸ / 1×10¯³⁰
F = 230.4 N
Therefore, the force exerted is 230.4 N
To solve this problem it is necessary to apply the concepts related to frequency and vibration of strings. Mathematically the frequency can be expressed as
Then the relation between two different frequencies with same wavelength would be
The beat frequency heard when the two strings are sounded simultaneously is
We have the velocity of the transverse waves in stretched string as
And,
Therefore the relation between the two is,
Finally substituting this value at the frequency beat equation we have
Therefore the beats per second are 11.92Hz
Answer:
a) 298.5 nm
, 522.4 nm and b) radiation frequency does not change
Explanation:
When electromagnetic radiation reaches a medium with a different index of refraction, the medium vibrates the molecules, as if it were a resonance process, whereby the medium vibrates at the same frequency as the incident light.
On the other hand, when the light reaches another medium its average speed within the medium changes, it is now less than the speed of light in a vacuum (c) for this to happen as we saw that the frequency is constant there must be a change in the wavelength of the radiation that is characterized by the ratio
λₙ = λ₀ / n
λₙ = 400 nm in the void
λₙ = 400 / 1.34
λₙ= 298.5 nm
λ₀ = 700 nm
λₙ = 700 / 1.34
λₙ = 522.4 nm
The radiation frequency does not change
