For each of the processes, determine whether the entropy of the system is increasing or decreasing. The system is underlined.

Heating carvone with aqueous sulfuric acid converts it into carvacrol. The mechanism involves the following steps:

Fittoniya [83]

Answer:

See figure 1

Explanation:

In this question, we have to start with the protonation of the double bond. In carvone we have two double bonds, so, we have to decide first which one would be protonated.

The problem states that the terminal alkene is the one that would is protonated. Therefore, we have to do the protonation in the double bond at the bottom to produce the carbocation number 1. Then, a hydride shift takes place to produce the carbocation number 2. A continuation, an elimination reaction takes place to produce the conjugated diene. Then the diene is protonated at the carbonyl group and with an elimination reaction of an hydrogen in the alpha carbon we can obtain carvacol. 

5 0

2 years ago

Calculate the number of hydrogen atoms in 33.0 g CH4

Elena-2011 [213]

Answer:

The number of hydrogen atoms is 4.96x10²⁴.

Explanation:

The number of atoms can be found with the following equation:

$n = N*\eta_{H}$

Where:

N: is the Avogadro's number = 6.022x10²³ atoms/mol

η: is the number of moles of hydrogen

n: is the number of hydrogen atoms

First, we need to find the number of hydrogen moles. The number of moles of CH₄ is:

$\eta_{CH_{4}} = \frac{m}{M}$

Where:

m: is the mass of methane = 33 g

M: is the molar mass of methane = 16.04 g/mol

$\eta_{CH_{4}} = \frac{33 g}{16.04 g/mol} = 2.06 mol$

Now, since we have 4 hydrogen atoms in 1 mol of methane, the number of moles of hydrogen is:

$\eta_{H} = 2.06\: mol\: CH_{4}*4 \frac{mol\: H}{mol \: CH_{4}} = 8.24 mol$

Hence, the number of hydrogen atoms is:

$n = N*\eta_{H} = 6.022 \cdot 10^{23} \: atoms/mol*8.24 mol = 4.96 \cdot 10^{24} atoms$

Therefore, the number of hydrogen atoms is 4.96x10²⁴.

I hope it helps you!

3 0

3 years ago

If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant

Vanyuwa [196]

<h3>Answer:</h3>

Excess Reagent = NBr₃

<h3>Solution:</h3>

The Balance Chemical Equation for the reaction of NBr₃ and NaOH is as follow,

2 NBr₃ + 3 NaOH → N₂ + 3 NaBr + 3 HBrO

Calculating the Limiting Reagent,

According to Balance equation,

2 moles NBr₃ reacts with = 3 moles of NaOH

So,

40 moles of NBr₃ will react with = X moles of NaOH

Solving for X,

X = (40 mol × 3 mol) ÷ 2 mol

X = 60 mol of NaOH

It means 40 moles of NBr₃ requires 60 moles of NaOH, while we are provided with 48 moles of NaOH which is Limited. Therefore, NaOH is the limiting reagent and will control the yield of products. And NBr₃ is in excess as some of it is left due to complete consumption of NaOH.

6 0

2 years ago

When iron, Fe, react with chlorine, Cl, the product is iron(II) chloride, FeCl. If 56.8 g of

Sauron [17]

Answer:

the answer is 25.032g check pic for explanation

4 0

3 years ago

Explain why the Amazon River does not create deltas?

jeka57 [31]

Answer:

The ocean currents are too strong by the Amazon River to form deltas.

Explanation:

The Atlantic has sufficient wave and tidal energy to carry most of the Amazon's sediments out to sea, thus the Amazon does not form a true delta. The great deltas of the world are all in relatively protected bodies of water, while the Amazon empties directly into the turbulent Atlantic.

4 0

2 years ago