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jarptica [38.1K]
3 years ago
13

For each of the processes, determine whether the entropy of the system is increasing or decreasing. The system is underlined.

Chemistry
1 answer:
defon3 years ago
6 0
1. Increasing
2. Increasing
3. Decreasing
4. Increasing
5. Decreasing
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49.2 m = _________ hm
dalvyx [7]
The answer is 0.492 because there are 100 meters in a hectometer, and 49.2/100 is 0.492
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Virtually no chemical reaction can occur in the body in the absence of enzymes. how might excessively high body temperature or a
olchik [2.2K]
1. The structural unit of nucleic acids are composed of repeating units of monomers called nucleotides. Nucelotides are composed of three functional groups: sugars which are specifically pentoses (5-Carbon sugars), phosphate group and nitrogenous base.

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3.
a. Based on the nitrogenous bases and sugar, the DNA has a deoxyribose as the sugar and its 4 bases are adenine, guanine, cytosine and thymine. For RNA, the sugar is ribose while its 4 bases are <span>adenine, guanine, cytosine, and uracil

b. Based on the </span>general three-dimensional structure, DNA is a double stranded β-helix with a long chain of nucleotides. RNA is composed of a shorter chain with a single strand α-helix structure.

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8 0
3 years ago
An enzyme can catalyze a reaction with either of two substrates, S1 or S2. The Km for S1 was found to be 2.0 mM, and the Km, for
Lera25 [3.4K]

Answer:

100.5 ≈ 101

Explanation:

Km for S1 = 2.0 mM

Km for S2 = 20 mM

Given that : S1 = S2 =  hence Vmax for either S1 or S2 can represent

The Vmax can be calculated using the data Given and equation below

Vo = Vmax [s] / ( Km + [s] )  ------ (1)

Vo = 0.5

[s] = 0.1 mM

km = 20 mM

making Vmax subject of  equation 1

Vmax = 0.5 ( 20.1 mM) / (0.1 mM )

         = 100.5 ≈ 101

3 0
3 years ago
Need answer ASAP!! The specific heat capacity of metal A is twice that of metal B. Based on
AURORKA [14]

Answer:

last choice

Explanation:

Specific heat of a metal is    j/kg-c

It says nothing about melting point or heat of fusion

A = twice B   =  2 * j/kg-c       B = j/kg-c

 if   j is constant and mass is the same we can write this more like

    A = 2 /C       and    B = 1/C

  or    A ~  C/2      and   B~  C

now you can see that the temp change in A   will be 1/2   that of B

4 0
2 years ago
Need Help!!! What else should I write?
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