Help please i need to know this

Mathematics

2 answers:

HACTEHA [7]3 years ago

8 0

Answer:true,true,false, true,false false

Step-by-step explanation:

scoundrel [369]3 years ago

8 0

Answer:

As shown in the attachment,

Step-by-step explanation:

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ella [17]

Sorry i don’t get it

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3 years ago

HELP?!? idk what im doing and nobody has asked this. will give brainliest answrr or whatever its called.

Illusion [34]

9514 1404 393

Answer:

$\textbf{A. }x=\dfrac{-4\pm2\sqrt{13}}{3}$

Step-by-step explanation:

First of all, subtract 12 from both sides of the equation to put it into standard form:

3x² +8x -12 = 0

Then identify the a, b, c of this form:

ax² +bx +c = 0

You see that a=3, b=8, c=-12.

Now use those values in the quadratic formula for the solutions:

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-8\pm\sqrt{8^2-4(3)(-12)}}{2(3)}\\\\x=\dfrac{-8\pm\sqrt{208}}{6}=\dfrac{-8\pm4\sqrt{13}}{6}\\\\\boxed{x=\dfrac{-4\pm2\sqrt{13}}{3}}\qquad\text{factor 2 from numerator and denominator}$

6 0

3 years ago

A baseball team has 15 field players and 10 pitchers. Each field player can take any of the 8 non-pitching positions. What is th

leonid [27]

Answer:

If order matters: 2,594,592,000 ways.

If order does not matter: 64,350 ways

Step-by-step explanation:

Assuming that the order matters when picking the non-pitching positions (since they are different positions), the number of possible different starting lineups is given by the permutation of picking 8 players out of 15, multiplied by 10 (pick one out of 10 pitchers):

$n =10*\frac{15!}{(15-8)!}\\ n=10*15*14*13*12*11*10*9*8\\n=2,594,592,000$

Now if the order of the field players is not important, the number of possible starting lineups is given by the combination of picking 8 players out 15, multiplied by 10:

$n = n =10*\frac{15!}{(15-8)!8!}\\ n=\frac{10*15*14*13*12*11*10*9*8}{8*7*6*5*4*3*2} \\n=64,350$