Answer:
1461.7 g of AgI
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂
From the balanced equation above,
1 mole of CaI₂ reacted to produce 2 moles of AgI.
Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:
From the balanced equation above,
1 mole of CaI₂ reacted to produce 2 moles of AgI.
Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI
Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:
Mole of AgI = 6.22 moles
Molar mass of AgI = 108 + 127
= 235 g/mol
Mass of AgI =?
Mass = mole × molar mass
Mass of AgI = 6.22 × 235
Mass of AgI = 1461.7 g
Therefore, 1461.7 g of AgI were obtained from the reaction.
Answer:
B
Explanation:
The particles are bound to each other and they vibrate at an almost undetectable rate.
Answer:
A. 11.1%
B. 0.0291
C. 1.57 M
D. 1.67 m
Explanation:
A.
Mass of KCl (solute): 28.0 g
Mass of water (solvent): 225 g
Mass of solution: 28.0 g + 225 g = 253 g
The mass percent of KCl is:
%KCl = (mass of KCl/mass of solution) × 100%
%KCl = (28.0 g/253 g) × 100%
%KCl = 11.1%
B.
The molar mass of KCl is 74.55 g/mol. The moles of KCl are:
28.0 g × (1 mol/74.55 g) = 0.376 mol
The molar mass of water is 18.02 g/mol. The moles of water are:
225 g × (1 mol/18.02 g) = 12.5 mol
The total number of moles is 0.376 mol + 12.5 mol = 12.9 mol.
The mole fraction of KCl is:
X(KCl) = moles of KCl / total moles
X(KCl) = 0.376 mol / 12.9 mol
X(KCl) = 0.0291
C.
The volume of the solution is 239 mL (0.239 L).
The molarity of KCl is:
M = moles of KCl / liters of solution
M = 0.376 mol / 0.239 L
M = 1.57 M
D.
The molality of KCl is:
m = moles of KCl / kilograms of solvent
m = 0.376 mol / 0.225 kg
m = 1.67 m
Answer:
B
Explanation:
when present
double bond the copound is alkene
Answer:
D
Explanation:
The amount of energy released or absorbed is equal the product of the mass, the specific heat capacity and the temperature change. The temperature change being the difference between the final and initial temperature.
Q = mc∆T
Q = heat energy (Joules, J) m = mass of a substance (kg) c = specific heat (units J/g∙K)
∆ is a symbol meaning "the change in" ∆T = change in temperature (Kelvins, K)
From the data provided in the question, we can deduce that:
Q = 16.7KJ = 16,700J
m = 225g
c = 1.74J/g.k
For the temperature, let the final temperature be f. This means our ∆T = f - 20
16,700 = 225 * 1.74 * (f - 20)
16700 = 391.5 (f - 20)
f - 20 = 16700/391.5
f - 20 = 42.7
f = 20 + 42.7 = 62.7
