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Natasha_Volkova [10]
3 years ago
6

PLssssss only need help with questions 2 and 4. I Will also give brianlist

Mathematics
1 answer:
inessss [21]3 years ago
3 0

Answer:

First oneB Second one A

Step-by-step explanation:

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The number 0.0000000726 is equivalent to which of the following expressions?
Dimas [21]

Answer:

E

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The label on the cars antifreeze container claims to protect the car between -30C and 130C. To convert Celsius temperature to Fa
RideAnS [48]
C = 5/9(F - 32)

C = -30
-30 = 5/9(F - 32)
-30 = 5/9F - 160/9
-30 + 160/9 = 5/9F
-270/9 + 160/9 = 5/9F
-110/9 = 5/9F
-110/9 * 9/5 = F
- 990/45 = F
- 22 = F

C = 5/9(F - 32)
C = 130

130 = 5/9F  - 160/9
130 + 160/9 = 5/9F
1170/9 + 160/9 = 5/9F
1330/9 = 5/9F
1330/9 * 9/5 = F
11970/45 = F
266 = F

So in Fahrenheit temp, the the car is protected between -22 F and 266 F

4 0
3 years ago
Read 2 more answers
A chain weighs 8 pounds per foot. How many ounces will 5 inches weigh? Round your answer to the nearest tenth as needed.
Butoxors [25]

Given that a chain weighs 8 pounds per foot.

We to find the weight in ounces per 5 inches.

It is known that 1 foot is equal to 12 inches and 1 pound is equal to 16 ounces.

Given that the weight is 8 pounds per foot.

\begin{gathered} 8\text{pounds per foot}=8\text{ pounds per 12 inches} \\ =16\times8\text{ ounces per 12 inches} \\ =128\text{ ounces per 12 inches} \\ =10.6\text{ ounces per inch} \\ =10.6\times5\text{ ounces per 5 inches} \\ =53\text{ ounces per 5 inches} \end{gathered}

Thus, the answer is 53 ounces in 5 inches.

7 0
1 year ago
A bag contains 10 red marbles, 8
zloy xaker [14]
The probability of it is 2/5
5 0
3 years ago
Please anyone answer me
ollegr [7]

Let's divide the shaded region into two areas:

area 1: x = 0 ---> x = 2

ares 2: x = 2 ---> x = 4

In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.

Area 1:

A\frac{}{1}  = ∫g(x)dx =  ∫xdx =  \frac{1}{2}  {x}^{2}  | \frac{2}{0}  = 2

Area 2:

A\frac{}{2}  = ∫(g(x) - f(x))dx

= ∫(x -  {(x - 2)}^{2} )dx

=  ∫( - {x}^{2}  + 5x - 4)dx

= ( - \frac{1}{3}{x}^{3} +   \frac{5}{2} {x}^{2}  - 4x)   | \frac{4}{2}

= 2.67 - ( - 0.67) = 3.34

Therefore, the area of the shaded portion of the graph is

A = A1 + A2 = 5.34

3 0
3 years ago
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