Answer:
11.3 g.
Explanation:
Hello there!
In this case, since the combustion of butane is:
Thus, since there is a 1:5 mole ratio between butane and water, we obtain the following mass of water:
Therefore, the resulting mass of water is:
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<em>V= 110mL = 110cm³ = 0,11dm³</em>
<em>C = 1,244 mol/L = 1,244 mol/dm³</em>
C = n/V
n = 1,244×0,11
<u>n = 0,13684 moles</u>
<em>mCa(OH)₂ = 74 g/mol</em>
1 mole Ca(OH)₂ ------------ 74g
0,13684 ---------------------- X
X = 74×0,13684
<u>X = 10,12616g</u>
:)
B) they have no charges and are inside an atom.*
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</span><span>Estrogen or testosterone
</span><span>Insulinlike growth factor-I (IGF-I)</span>
