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3 years ago

In the periodic table, a set of properties repeats from

Chemistry

2 answers:

solong [7]3 years ago

5 0

Explanation:

The vertical rows in a periodic table are called rows. Whereas columns in a periodic table are called group.

So, elements in a periodic table when arranged in a period then they tend to repeat their properties because when the row repeats then elements with similar properties fall under same groups.

Thus, we can conclude that in the periodic table, a set of properties repeats from row to row.

jok3333 [9.3K]3 years ago

3 0

in the periodic table, a set of properties repeats from row to row

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Select the answer that CANNOT be used to fill in the blank in the following sentence:

8_murik_8 [283]

Answer:

the answer is ur mom

Explanation:

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3 years ago

A 101.2 ml sample of 1.00 m naoh is mixed with 50.6 ml of 1.00 m h2so4 in a large styrofoam coffee cup; the cup is fitted with a

Murrr4er [49]

The enthalpy change of the reaction when sodium hydroxide and sulfuric acid react can be calculated using the mass of solution, temperature change, and specific heat of water.

The balanced chemical equation for the reaction can be represented as,

$H_{2}SO_{4}(aq) + 2NaOH (aq) ----> Na_{2}SO_{4}(aq) + 2H_{2}O(l)$

Given volume of the solution = 101.2 mL + 50.6 mL = 151.8 mL

Heat of the reaction, q = $m C .$ Δ $T$

m is mass of the solution = 151.8 mL * $\frac{1 g}{1 mL} = 151.8 g$

C is the specific heat of solution = 4.18 $\frac{J}{g. ^{0}C}$

ΔT is the temperature change = $31.50^{0}C - 21.45^{0}C = 10.05^{0}C$

q = $151.8 g (4.18 \frac{J}{g ^{0}C})(10.05^{0}C) = 6377 J$

Moles of NaOH = $101.2 mL * \frac{1L}{1000 mL}*\frac{1.00 mol}{L} = 0.1012 mol$ NaOH

Moles of $H_{2}SO_{4}$ = $50.6 mL * \frac{1 L}{1000 mL} * \frac{1.0 mol}{1 L} = 0.0506 mol H_{2}SO_{4}$

Enthalpy of the reaction = $\frac{6377 J*\frac{1kJ}{1000J}}{0.0506 mol} = 126 kJ/mol$

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3 years ago

What might go wrong while heating a substance<br> with a candle?

GaryK [48]

Answer:

the wax melts

Explanation:

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7 0

2 years ago

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Evaluate the carbon dioxide molecule. Explain how to determine if double or triple bonds exist in the molecule.

S_A_V [24]

Answer:

It contain double Bond.

Explanation:

To determine weather the bond is double or triple simply check the electron involved in mutual sharing of an electron if 2 electron takes parts it said to be double or if 3 it said to be triple.

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3 years ago

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3 years ago