2C₂H₂ + 5O₂ = 4CO₂ + 2H₂O
m(CO₂)/{4M(CO₂)} = m(C₂H₂)/{2M(C₂H₂)}
m(CO₂)=2M(CO₂)m(C₂H₂)/M(C₂H₂)
m(CO₂)=2*44g/mol*38.9g/26g/mol = 131.7 g
131.7 grams of carbon dioxide would be formed
The temperature in kelvin does 60.5 liters of sulfur dioxide occupy if there are 2.5 mole at 0.75 atm is 221.07 kelvin
Explanation
This is calculated using ideal gas equation, that is PV=nRT
where, P(pressure) = 0.75 atm
V(volume) = 60.5 L
n(moles) = 2.5 mole
R( gas constant) = 0.0821 L.atm/mol.k
T(temperature =?
by making T the subject of the formula
T is therefore =Pv/nR
T= (0.75 atm x 60.5 L) / ( 2.5 molex 0.0821 L.atm/mol.K) = 221.07 kelvins
The question is incomplete , the complete question is;
The mass of each Wt isotope is measured relative to C-12 and tabulated below. Use the mass of C-12 to convert each of the masses to amu and calculate the atomic mass of Wt.
Wt-296 = 24.6622
Answer:
The atomic mass of Wt-296 is 195.9464 amu.
Explanation:
1 amu is defined as 1 by twelfth of the carbon-12 mass.
Mass of an isotope Wt-296 = 24.6622
Mass of an isotope Wt-296 in amu = M
The atomic mass of Wt-296 is 195.9464 amu.
The energy of the electron reduces as it moves closers to the nucleus. This is because it moves from a higher energy orbital to a one of lower energy. It does this by releasing a photon with the energy difference of the current energy level, and the energy level it drops too.
They have strong intermolecular forces between their atoms, hence why more heat is necessary.
