Answer:
They are multilayered
Spacesuits provide protection from radiation and offer normal air pressure inside
Explanation:
<u>Answer:</u> The density of gold in
is ![19.22g/cm^3](https://tex.z-dn.net/?f=19.22g%2Fcm%5E3)
<u>Explanation:</u>
Density is defined as the ratio of mass of the object and volume of the object. Mathematically,
![\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}](https://tex.z-dn.net/?f=%5Ctext%7BDensity%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20the%20object%7D%7D%7B%5Ctext%7BVolume%20of%20the%20object%7D%7D)
We are given:
Density of gold = ![1200lb/ft^3](https://tex.z-dn.net/?f=1200lb%2Fft%5E3)
Using conversion factors:
1 lb = 453.6 g
1 feet = 12 inches
1 inch = 2.54 cm
Converting given quantity into
, we get:
![\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3](https://tex.z-dn.net/?f=%5CRightarrow%20%28%5Cfrac%7B1200lb%7D%7Bft%5E3%7D%29%5Ctimes%20%28%5Cfrac%7B453.6g%7D%7B1lb%7D%29%5Ctimes%20%28%5Cfrac%7B1ft%7D%7B12inch%7D%29%5E3%5Ctimes%20%28%5Cfrac%7B1inch%7D%7B2.54cm%7D%29%5E3%5C%5C%5C%5C%5CRightarrow%2019.22g%2Fcm%5E3)
Hence, the density of gold in
is ![19.22g/cm^3](https://tex.z-dn.net/?f=19.22g%2Fcm%5E3)
Answer:
![V_{LiOH}=21.8mL](https://tex.z-dn.net/?f=V_%7BLiOH%7D%3D21.8mL)
Explanation:
Hello,
In this case, during titration at the equivalence point, we find that the moles of the base equals the moles of the acid:
![n_{LiOH}=n_{HBr}](https://tex.z-dn.net/?f=n_%7BLiOH%7D%3Dn_%7BHBr%7D)
That it terms of molarities and volumes we have:
![M_{LiOH}V_{LiOH}=M_{HBr}V_{HBr}](https://tex.z-dn.net/?f=M_%7BLiOH%7DV_%7BLiOH%7D%3DM_%7BHBr%7DV_%7BHBr%7D)
Next, solving for the volume of lithium hydroxide we obtain:
![V_{LiOH}=\frac{M_{HBr}V_{HBr}}{M_{LiOH}} =\frac{0.0759M*25.0mL}{0.0896M} \\\\V_{LiOH}=21.8mL](https://tex.z-dn.net/?f=V_%7BLiOH%7D%3D%5Cfrac%7BM_%7BHBr%7DV_%7BHBr%7D%7D%7BM_%7BLiOH%7D%7D%20%3D%5Cfrac%7B0.0759M%2A25.0mL%7D%7B0.0896M%7D%20%5C%5C%5C%5CV_%7BLiOH%7D%3D21.8mL)
Best regards.
Explanation:
Here I send you all the 3 elements that you are asking for.
Notice that first on the left you will find lewis structure, then condensed and finally chemical formula of each of the compound you enlisted.