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3 years ago

Please help me with this!!! i’m begging!

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

3 0

Answer:

Domain is 3 <x>_-2

Range is 6 <x>_-3 (the lines are supposed to be under the >. it means equal to)

Step-by-step explanation:

First look on the x-axis, is goes from 3 to -2. now look at the colored in dot. that means more than or equal to. So the sign of -2 is x >_ -2. put the 3 on the other side. It stops at three so the sign is > 3. so 3<x>_ -2

Do the same with the y-axis except look up and down instead of left and right. so the numbers are 6 and -3. Use the same method above. this is set builder notation.

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3 years ago

Describe how to draw a tape diagram to represent and answer 3÷3/5=? 3 ÷ 3/5 = ? for a friend who was absent.

enyata [817]

Answer:

The numerical answer is 5

Please see the tape diagram evolution in the attached image

Step-by-step explanation:

Start by drawing three unit tapes, and divide each one of them in 5 equal parts since we need to be dividing the quantity 3 by 3/5 (denominator 5)

In the second step, join the three tapes in one long one maintaining the original divisions.

In the third step, select groups of 3 divisions (recall you need to divide by 3/5) which will identify in your tape how many of these 3/5 groups you have.

Finally count the number of 3/5 groups you found in the collection of the three original tapes placed together. You should count a total of 5 of these 3/5 groups.

5 then tells you what is the quotient of 3 divided in 3/5

4 0

3 years ago

Helpppp pleaseeeeeeeeeeeeeee

Vesna [10]

Answer:

Find below the calculations of the two areas, each with two methods. The results are:

Upper triangle:

$Area=5000\sqrt{3}units^2$

Lower triangle:

$Area=14,530m^2$

Explanation:

A) Method 1

When you are not given the height, but you are given two sides and the included angle between the two sides, you can use this formula:

$Area=side_1\times side_2\times sin(\alpha)$

Where, $\alpha$ is the measure of the included angle.

1. Upper triangle:

$side_1=200units\\ \\ side_2=100units\\ \\ \alpha =60\º\\ \\ Area=200units\times 100units\times sin(60\º)/2\\ \\ Area=5000\sqrt{3}units^2$

2. Lower triangle:

$side_1=231m\\ \\ side_2=150m\\ \\ \alpha =123\º\\ \\ Area=231m\times 150m\times sin(123\º)/2\\ \\ Area=14,529.96m^2\approx14,530m^2$

B) Method 2

You can find the height of the triangle using trigonometric properties, and then use the very well known formula:

$Area=(1/2)\times base\times height$

Use it for both triangles.

3. Upper triangle:

The trigonometric ratio that you can use is:

$sine(\alpha)=opposite\text{ }leg/hypotenuse$

Notice the height is the opposite leg to the angle of 60º, and the side that measures 100 units is the hypotenuse of that right triangle. Then:

$sin(60\º)=height/100units\\ \\ height=sin(60\º)\times100units\\ \\ height=50\sqrt{3}units$

$Area=(1/2)\times base\times height=(1/2)\times 200units\times 50\sqrt{3}units=5,000\sqrt{3}units^2$

3. Lower triangle:

$sin(180\º-123\º)=height/231m\\ \\ height=sin(57\º)\times 231m\\ \\ height=193.7329m^2$

$Area=(1/2)\times base\times height=(1/2)\times 150m\times 193.7329m^2\\\\ Area=14,529.96m^2\approx 14,530m^2$

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3 years ago

Evaluate the expression where x=5 and y =2

solong [7]

Answer:

Step-by-step explanation:

8 0

3 years ago