Answer:
A) 1.76U×10⁻³N
B) 2.716×10⁻³N
C) 264.5⁰
Explanation:
See detailed workings for (a), (b), (c) attached.
When the launch velocity is a bit less than the escape velocity, the satellite with time will find itself back to earth and when the speed is far beyond the escape velocity, the satellite with time, be lost in space.
The velocity of escape from the less massive Moon is about 2.4 km per second at its surface. ... A planet (or satellite) cannot long retain an atmosphere if the planet's escape velocity is low enough to be near the average velocity of the gas molecules making up the atmosphere.
Answer:
radial acceleration is 41.8 m / s²
Explanation:
The acceleration for circular motion is
a = v² / r
They also give us the X and Y position where the body falls when the rope breaks, let's write the projectile launch equations
x = vox t
y = v₀ₓ t - ½ g t2
Since the circle is horizontally the v₀ₓ is zero (v₀ₓ = 0)
x = v₀ₓ t
t = x / v₀ₓ
y = - ½ g t²
Let's replace and calculate the initial velocity on the X axis
y = - ½ g (x / vox)²
v₀ₓ = √ (g x² / 2 y)
v₀ₓ = √ [- (-9.8) 1.6² / (2 1.00)]
v₀ₓ = 3.54 m / s
This is the horizontal velocity, but since it circle is in horizontal position it is also the velocity of the body at the point of rupture.
Now we can calculate the radial acceleration
a = v² / r
a = 3.54² / 0.300
a = 41.8 m / s²
Answer:
I looked it up but got perihelion so I don't know if that will help at all but try um.... I don't know try L
Explanation:
Answer:
C
Explanation:
The name of the rock is usually derived from the sediment grain size.
