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3 years ago

All of the following are types of symbiotic relationships except for

Physics

1 answer:

nevsk [136]3 years ago

3 0

The answer is D. the way I remember it is they all end with -alism.

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In the combo circuit diagrammed, R1 = 19.2 Ω, R2 = 20.7 Ω, and R3 = 25.8 Ω. Find the equivalent resistance of the circuit.

garik1379 [7]

Answer:

Equivalent resistance: 13.589 Ω

Explanation:

R series = R1 + R2 + R3 ...

$\frac{1}{R_{eq} } = \frac{1}{R1} +\frac{1}{R2} +\frac{1}{R3} ...$

Find the equivalent resistance of the right branch of the circuit:

$R_{eq} = R_{2} +R_{3} \\R_{eq} = 20.7 + 25.8 = 46.5 ohms$

$\frac{1}{R_{eq} } = \frac{1}{19.2} +\frac{1}{46.5}\\\\\frac{1}{R_{eq} } = 0.0735887097\\\\R_{eq} = 13.5890411$

6 0

2 years ago

On a sunny summer day, why does a white car with a light-colored interior stay cooler than a black car with a dark-colored inter

Oduvanchick [21]

Answer: Solar radiation reflects off the lighter colours, away from the car, thus keeping the car cool

Explanation: This is because lighter colors reflect a good amount of radiation while darker colors absorb it. Just like, Antarctica hasn't completely melted because it reflects a lot of the heat that is acting upon it. Or, you notice that you get hotter when you wear a black shirt opposed to a white one.

8 0

3 years ago

An athlete completes 1 laps around a track with a radius of 25 meters in 180 seconds. What is the magnitude of the athlete's tan

DanielleElmas [232]

Answer:

0.872m/s

Explanation:

Tangential velocity is given by the formula,

$v= 2\pi r/ t$

In the question given,

radius= 25meters

time= 180secs

pie= 3.14

number of laps= 1

The magnitude of tangential velocity equals;

$\frac{1lap* 2 *3.14 *25m}{180secs}$

v = 157m/180secs

Therefore, the magnitude of the tangential velocity

=0.872m/secs

5 0

3 years ago

Why are nuclear power plants controversial

Sliva [168]

Because a nuclear meltdown can be caused if systems fail.

6 0

3 years ago

15 points. give me the method.

AveGali [126]

Answer:

$\boxed{{160 \: m(s)}^{ - 1} }$

Explanation:

$if \:the \: frequencies \: are \to \\ f_{1} = 640Hz \\ and \\f_{2} = 480Hz \: \\ but \: \boxed{v = f \gamma }: f = \frac{v}{ \gamma } \\ if \: \gamma_{1} - \gamma _{2} = 1 = \gamma \\ f_{1} - f_{2} = 640 - 480 = \boxed{ 160Hz} = f \\ v = f \gamma = 160 \times 1 = \boxed{{160 \: m(s)}^{ - 1} }$

5 0

3 years ago