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2 years ago

How to solve for time given distance and velocity

Physics

1 answer:

Virty [35]2 years ago

8 0

Answer:

Well, I think you're talking about kinematics, especially uniform rectilinear motion. We know that there is a specific equation for that:

S = Vt + S0

With S being the distance, V the velocity, t the time and S0 the initial distance (initial displacement).

From this you can calculate t, if that's what you want.

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A tiger leaps horizontally out of a tree that is 6.00 m high. If he lands 2.00 m from the base of the tree, calculate his initia

Musya8 [376]

Answer:

The initial speed of the tiger is 1.80 m/s

Explanation:

Hi there!

The equation of the position vector of the tiger is the following:

r = (x0 + v0 · t, y0 + 1/2 · g · t²)

Where:

r = position vector at a time t.

x0 = initial horizontal position.

v0 = initial horizontal velocity.

t = time.

y0 = initial vertical position,

g = acceleration due to gravity.

Let´s place the origin of the frame of reference on the ground at the point where the tree is located so that the initial position vector will be:

r0 = (0.00, 6.00) m

We can use the equation of the vertical component of the position vector to obtain the time it takes the tiger to reach the ground.

y = y0 + 1/2 · g · t²

When the tiger reaches the ground, y = 0:

0 = 6.00 m - 1/2 · 9.81 m/s² · t²

2 · (-6.00 m) / -9.81 m/s² = t²

t = 1.11 s

We know that in 1.11 s the tiger travels 2.00 m in the horizontal direction. Then, using the equation of the horizontal component of the position vector we can find the initial speed:

x = x0 + v0 · t

At t = 1.11 s, x = 2.00 m

x0 = 0

2.00 m = v0 · 1.11 s

2.00 m / 1.11 s = v0

v0 = 1.80 m/s

The initial speed of the tiger is 1.80 m/s

4 0

3 years ago

A student adds ice to 150 mL of water. She observes that the temperature of the water decreases after 10 minutes. Which statemen

Step2247 [10]

Answer:

3- kinetic energy was transferred from the water to the ice

Explanation:

the kinetic energy in this situation is the molecules vibrating so the molecules in the ice absorb it and make the molecules not vibrate so it gets colder

3 0

3 years ago

Why might this cloud formation be termed the “Pillars of Creation"?

Oduvanchick [21]

Answer:

I think the answer might be A

Explanation:

because if its called Pillars creation then something important might be being born maybe

7 0

2 years ago

Read 2 more answers

Adam and Natalie push on a cart using 150 N of force.The cart does not move.What is static friction on the cart?

Roman55 [17]

When force is applied on an object the object will not slide

So here object will remain in equilibrium after applying the force

So in this case the condition of equilibrium is maintained due to friction force that is applied on the object.

So here for equilibrium be can say

$F_{net} = 0$

also we know that

$F_{net} = F - F_f$

we are given that

$F = 150 N$ ( applied force on the box)

$F_{net} = 150 - F_f = 0$

$F_f = 150 N$

So here this friction force on the cart is known as static friction

$F_s = 150 N$

4 0

3 years ago

Read 2 more answers

A hockey puck sliding on smooth ice at 4 m/s comes to a 1-m-high hill. Will it make it to the top of the hill?

solniwko [45]

Answer:

No it will not make to the top of the hill

Explanation:

From the question we are told that

The velocity is $v = 4 \ m/s$

The height of the hill is $h = 1 \ m$

Generally from the law of energy conservation we have that

The kinetic energy of the pluck at the level position = The potential energy of the pluck at the maximum height the pluck can get to

$\frac{1}{2} * m * v^2 = m * g * h_{max}$

=> $\frac{1}{2} * v^2 = g * h_{max}$

=> $h_{max} = \frac{0.5 * v^2}{g}$

=> $h_{max} = 0.8163 \ m$

Given that the maximum height which the pluck can get to at this speed given in the question is less than the height of the hill then conclusion will be that the pluck will not make it to the top of the hill

3 0

3 years ago