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Kryger [21]
3 years ago
5

HELPPPP ITS DUE TODAY

Chemistry
1 answer:
AnnZ [28]3 years ago
6 0

Answer:

Option C is correct : Calcium and magnesium are alkaline earth metals.

Explanation:

From the given option C is correct.

Calcium and magnesium are alkaline earth metals. Both are present in group 2. Each have 2 valence electrons.

All other options are incorrect, because:

a) Chlorine and iodine are alkali metals.

Chlorine and iodine are not alkali metals. These are halogens. Both have seven valence electrons and form salt with alkali metals.

B) Potassium and phosphorus are in the same group.

Potassium and phosphorus are not present in same groups. Potassium is present in group 1 and phosphorus is present in group 15.

d) Boron and silicon are present in same period.

Boron and silicon are not present in same period. Boron is present in period 2 while silicon is present in period 3.

e) Lead and tin both are non metals.

This option is also incorrect because lead and tin both are metals.

Thus, only option C is correct.

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Toy balloons are filled with hydrogen gas, at standard temperature, from a 10.0-liter cylinder. the initial pressure of the gas
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To answer this item, we are to assume that the given gas behaves ideally such that it can follow one of the simplified ideal gas law as written below,

                  P₁V₁ = P₂V₂

where P is the pressure and V is the volume. 

Substituting the known values, while V₂ is unknown,

                 (100 atm)(10 L) = (1 atm)(V₂)

The value of V₂ is calculated to be equal to 1000 L. 

The number of balloons that can be filled is as calculated.
                      n = (1000 L) / (1 L / balloon)
                               n = 1000
7 0
3 years ago
What is the iupac name of ch3ch2ch2ch2ch2ch3
Alborosie

Answer:

hexane

Explanation:

3 0
3 years ago
All of the halogens, group 17, have seven valence electrons. which of these would represent the oxidation number of the halogens
fomenos
It depends if it occurs naturally it has oxidation number of 0
but when it react with other element it has an oxidation number of -1
6 0
2 years ago
How many molecules of XeF6 are formed from 12.9 L of F2 (at 298 K and 2.6 atm) according to 11) the following reaction? Assume t
ddd [48]

Answer:

#Molecules XeF₆ = 2.75 x 10²³ molecules XeF₆.

Explanation:

Given … Excess Xe + 12.9L F₂ @298K & 2.6Atm => ? molecules XeF₆

1. Convert 12.9L 298K & 2.6Atm to STP conditions so 22.4L/mole can be used to determine moles of F₂ used.

=> V(F₂ @ STP) = 12.6L(273K/298K)(2.6Atm/1.0Atm) = 30.7L F₂ @ STP

2. Calculate moles of F₂ used

=> moles F₂ = 30.7L/22.4L/mole = 1.372 mole F₂ used

3. Calculate moles of XeF₆ produced from reaction ratios …

Xe + 3F₂ => XeF₆ => moles of XeF₆ = ⅓(moles F₂) = ⅓(1.372) moles XeF₆ = 0.4572 mole XeF₆

4. Calculate number molecules XeF₆ by multiplying by Avogadro’s Number  (6.02 x 10²³ molecules/mole)

=> #Molecules XeF₆ = 0.4572mole(6.02 x 10²³ molecules/mole)

                                  = 2.75 x 10²³ molecules XeF₆.

8 0
2 years ago
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