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son4ous [18]
2 years ago
10

A sample of Ar(g) is contained in a

Chemistry
1 answer:
Elina [12.6K]2 years ago
5 0

Answer:

Option (B) is correct.

Explanation:

Initial temperature of the gas is T.

The volume of the  sample is decreased from 4.5 L to 1.5 L  while the pressure is held constant.

At constant pressure, the relation between volume and temperature is given by :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Here, V₁ = 4.5 L, V₂ = 1.5 L, T₁ = T₁, T₂ = ?

So,

T_2=\dfrac{V_2T_1}{V_1}\\\\T_2=\dfrac{1.5\times T_1}{4.5}\\\\T_2=\dfrac{T_1}{3}

So, the final temperature of the gas is \dfrac{T_1}{3}. Hence, the correct option is (B).

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The volume of a 2.49 g sample of gas is 752 mL at 1.98 atm and 62 C What is the gas?
creativ13 [48]

Answer:

The volume of a sample of gas (2.49 g) was 752 mL at 1.98 atm and 62∘C 62 ∘ C .

6 0
3 years ago
How much thermal energy is added to 10.0 g of ice at −20.0°C to convert it to water vapor at 120.0°C?
Sonbull [250]

Answer:

7479 cal.

31262.2 joules

Explanation:

This is a calorimetry problem where water in its three states changes from ice to vapor.

We must use, the calorimetry formula and the formula for latent heat.

Q = m . C . ΔT

Q = Clat . m

First of all, let's determine the heat for ice, before it melts.

10 g . 0.5 cal/g°C ( 0° - (-20°C) = 100 cal

Now, the ice has melted.

Q = Clat heat of fusion . 10 g

Q = 79.7 cal/g . 10 g → 797 cal

We have water  at 0°, so this water has to receive heat until it becomes vapor. Let's determine that heat.

Q = m . C . ΔT

Q = 10 g . 1 cal/g°C (100°C - 0°C) → 1000 cal

Water is ready now, to become vapor so let's determine the heat.

Q = Clat heat of vaporization . m

Q = 539.4 cal/g . 10 g → 5394 cal

Finally we have vapor water, so let's determine the heat gained when this vapor changes the T° from 100°C to 120°

Q = m . C . ΔT

Q = 10 g . 0.470 cal/g°C . (120°C - 100°C) → 94 cal

Now, we have to sum all the heat that was added in all the process.

100 cal + 797 cal + 1000 cal + 5394 cal + 94 cal =7479 cal.

We can convert this unit to joules, which is more acceptable for energy terms.

1 cal is 4.18 Joules.

Then, 7479 cal are (7479 . 4.18) = 31262.2 joules

6 0
3 years ago
Which would be an example of a compound?<br> oxygen<br> carbon dioxide<br> sand<br> carbon
GenaCL600 [577]

Answer:

carbondioxide is an example of compound.

4 0
3 years ago
10 + 32 -6=any one?​
Kryger [21]

Answer:

Your answer will be 36

Explanation:

10+32=42

42-6=36

3 0
3 years ago
What is the percent composition in chloric acid (HClO3)?
Nuetrik [128]
Total weight = 1 + 35.45 + 3 * 16 = 84.45

H = 1 / 84.45 * 100% = 1.18%
Cl = 35.45 / 84.45 * 100% = 41.98%
O = 48 / 84.45 * 100% = 56.84%
7 0
2 years ago
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