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son4ous [18]
2 years ago
10

A sample of Ar(g) is contained in a

Chemistry
1 answer:
Elina [12.6K]2 years ago
5 0

Answer:

Option (B) is correct.

Explanation:

Initial temperature of the gas is T.

The volume of the  sample is decreased from 4.5 L to 1.5 L  while the pressure is held constant.

At constant pressure, the relation between volume and temperature is given by :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Here, V₁ = 4.5 L, V₂ = 1.5 L, T₁ = T₁, T₂ = ?

So,

T_2=\dfrac{V_2T_1}{V_1}\\\\T_2=\dfrac{1.5\times T_1}{4.5}\\\\T_2=\dfrac{T_1}{3}

So, the final temperature of the gas is \dfrac{T_1}{3}. Hence, the correct option is (B).

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Answer:

living organisms whose genetic material has been artificially manipulated in a laboratory through genetic engineering

Explanation:

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This time the answer is quantitive because the mentions numbers

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What is the relative rate of effusion for hydrogen iodide (128 g/mol) compared to gaseous hydrochloric acid (36.5 g/mol)
MArishka [77]

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8 0
3 years ago
If two balls have the same volume, but ball A has twice as much mass as ball B, which one will have the greater density? ball A,
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Density (D) is defined as the amount or mass (m) of a substance present in a unit volume(V). It can be expressed mathematically as:

Density = Mass/Volume

i.e. D = m/V -------(1)

Units: g/cm3

a)

If m1, V1 and D1 = mass, volume  and density respectively of ball A

m2, V2 and D2 = mass, volume and density respectively of ball B

It is given that: V1 = V2; but m1 = 2m2

Based on equation (1) we have:

D1/D2 = (m1/V1)* (V2/m2) = (2m2/V2)*(V2/m2) = 2

Thus, density of ball A is twice that of B.

Ans: Ball A will have a greater density than B

b)

If m1, V1 and D1 = mass, volume  and density respectively of ball C

m2, V2 and D2 = mass, volume and density respectively of ball D

It is given that:

V1 = 3V2 and m2 = 1/3(m1) i.e m1 = 3m2

Therefore,

D1/D2 = (m1/V1)* (V2/m2) = (3m2/3V2)*(V2/m2) = 1

Thus, D1 = D2

Ans: Their densities are equal

c)

If m1, V1 and D1 = mass, volume  and density respectively of ball P

m2, V2 and D2 = mass, volume and density respectively of ball Q

It is given that:

m1 = m2 but V1 = 2V2

Therefore,

D1/D2 = (m1/V1)* (V2/m2) = (m2/2V2)*(V2/m2) = 1/2

Thus, D1 = 1/2(D2)

Ans: Ball Q will have a greater density.

d)

If m1, V1 and D1 = mass, volume  and density respectively of ball X

m2, V2 and D2 = mass, volume and density respectively of ball Y

It is given that:

V1 = 2V2 and m1 = 1/2(m2)

Therefore,

D1/D2 = (m1/V1)* (V2/m2) = ((1/2(m2)/2V2)*(V2/m2) = 1/4

Thus, D1 = 1/4(D2)

Ans: Ball Y will have a greater density.



5 0
3 years ago
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If liquid water is exposed to normal atmospheric pressure, what needs to change in order to change its state of matter?
inn [45]

Answer: Option (b) is the correct answer.

Explanation:

State of a substance changes when heat is provided to a substance.

This is because when we heat water then intermoleclar forces present within its molecules tend to break down. Due to this molecules start to move away from each other.

As a result, kinetic energy of molecules increases and they collide rapidly. Hence, solid state of water changes into liquid state and upon excessive heating liquid state of water changes into vapor state.

Thus, we conclude that temperature of water needs to change in order to change its state of matter.

6 0
3 years ago
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