Answer:E
Explanation:
The electron is expected to be in any of the 4p orbitals. For the 4p orbitals
n=4
l=1
ml=-1,0,1
ms=-1/2 or +1/2
All the ml and ms configurations are equiprobable hence the answer.
Answer: the molarity of the solution in volumetric flask "B' is 0.0100 M
Explanation:
Given that;
the Molarity of stock solution M₁ = 1.25M
The molarity os solution in volumetric flask A (M₂) = M₂
Volume of stock solution pipet out (V₁) = 5.00mL
Volume of solution in volumetric flask A V₂ = 25.00mL
using the dilution formula
M₁V₁ = M₂V₂
M₂ = M₁V₁ / V₂
WE SUBSTITUTE
M₂ = ( 1.25 × 5.00 ) / 25.00 mL
M₂ = 0.25 M
Now volume of solution pipet out from volumetric flask A V₂ = 2.00 mL
Molarity of solution in volumetric flask B (M₃) = M₃
Volume of solution in volumetric flask B V₃ = 50.00m L
Using dilution formula again
M₂V₂ = M₃V₃
M₃ = M₂V₂ / V₃
WE SUBSTITUTE
M₃ = ( 0.25 × 2.0) / 50.0
M₃ = 0.0100 M
Therefore the molarity of the solution in volumetric flask "B' is 0.0100 M
When uranium<span> comes in contact with oxygen in the air, it rusts, just like iron does, but </span>uranium<span> rust is black and not red. Like other heavy </span>atoms <span>such as iron, </span>uranium atoms<span> have more neutrons than they do protons. Not all </span>uranium atoms<span> have the </span>same<span> number of neutrons.</span>
Answer: 1 mol of 
will be produced from this reaction.
Explanation: Reaction follows,
As seen from the balanced chemical equation above, we get
For every 3 moles of Aluminium and 3 moles of 
, 1 mole of 
is formed.
For every 3 moles of Aluminium and 3 moles of , 1 mole of is formed.
For every 3 moles of Aluminium and 3 moles of , 3 moles of 
is formed.
For every 3 moles of Aluminium and 3 moles of , 6 moles of 
is formed.
