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3 years ago

Adding energy to an object increases its _____________ .

1 answer:

3 0

Good Morning

Adding energy to an object increases its_____?

It depends on which type of energy you use, like heat energy can increase an objects temperature.

Adding light energy can increase an objects brightness.

There are many types of energy, but some won't change objects or increases/decreases something in a object

Hope this helps

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A student was given four unknown solutions. Each solution was checked for. conductivity and tested with. phenolphthalein. The re

777dan777 [17]

Answer: (3) C

Explanation:

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2 years ago

What is the change in enthalpy when 11. 0 g of liquid mercury is heated by 15°c?

Vlad1618 [11]

Enthalpy change is the difference between energy used and energy gained. The change in enthalpy of the liquid mercury is 0.0231 kJ.

<h3>What is the enthalpy change?</h3>

Enthalpy change is the difference between the energy used to break chemical bonds and the energy gained by the products formed in a chemical reaction.

The enthalpy change is given by,

$\rm \Delta H_{rxn} = \rm q_{rxn}$

and,

$\rm q = mc\Delta T$

Given,

Mass of the liquid mercury (m) = 11.0 gm

The specific heat of mercury (c) = 0.14 J per g per degree Celsius

Temperature change = 15 degrees Celsius

Enthalpy change is calculated as:

$\begin{aligned} \rm q &= \rm mc\Delta T\\\\&= 11 \times 0.14 \times 15\\\\&= 23.1 \;\rm J\end{aligned}$

Therefore, 0.0231 kJ is the change in enthalpy.

Learn more about enthalpy change here:

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2 years ago

What is the meaning of the word organism

Lady_Fox [76]

Answer:

B) any complex thing with properties normally associated with living things

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2 years ago

Read 2 more answers

When 0.200 grams of Al reacts with 15.00 mL of a 0.500 M copper(II) chloride solution, how many moles of solid Cu would be produ

Naddik [55]

When The balanced equation is:
2Al + 3CuCl2 ⇒3 Cu + 2AlCl3
So, we want to find the limiting reactant:
1- no. of moles of 2Al = MV/n = (Wt * V )/ (M.Wt*n*V) = Wt / (M.Wt *n)

where M= molarity, V= volume per liter and n = number of moles in the balanced equation.
by substitute:
∴ no. of moles of 2Al = 0.2 / (26.98 * 2)= 0.003706 moles.
2- no.of moles of 3CuCl2= M*v / n = (0.5*(15/1000)) / 3= 0.0025 moles.
So, CuCl2 is determining the no.of moles of the products.
∴The no. of moles of 3Cu = 0.0025 moles.
∴The no.of moles of Cu= 3*0.0025= 0.0075 moles.
and ∵ amount of weight (g)= no.of moles * M.Wt = 0.0075 * M.wt of Cu
= 0.0075 * 63.546 =0.477 g

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2 years ago

The metals in Groups 1A, 2A, and 3A ____.

Ket [755]

The correct answer is D.

I hope that helped! c:

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3 years ago