1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GREYUIT [131]
3 years ago
12

What are four properties of water?

Chemistry
1 answer:
Nana76 [90]3 years ago
5 0

Answer:

Polarity

Cohesion  

Adhesion

High Specific Heat

Explanation:

You might be interested in
Answer and work for this problem
MArishka [77]
We can write the balanced equation for the synthesis reaction as 
     H2(g) + Cl2(g) → 2HCl(g)

We use the molar masses of hydrogen chloride gas HCl and hydrogen gas H2 to calculate for the mass of hydrogen gas H2 needed:
     mass of H2 = 146.4 g HCl *(1 mol HCl / 36.46 g HCl) * (1 mol H2 / 2 mol HCl) * 
                           (2.02 g H2 / 1 mol H2)                        
                        = 4.056 g H2

We also use the molar masses of hydrogen chloride gas HCl and chlorine gas CL2 to calculate for the mass of hydrogen gas H2:
     mass of CL2 = 146.4 g HCl *(1 mol HCl / 36.46 g HCl) * (1 mol Cl2 / 2 mol HCl) *
                             (70.91 g Cl2 / 1 mol Cl2)
                          = 142.4 g Cl2 

Therefore, we need 4.056 grams of hydrogen gas and 142.4 grams of chlorine gas to produce 146.4 grams of hydrogen chloride gas.
6 0
3 years ago
Americans eat too much salt (NaCl). A healthy adult should eat no more than 6 g of salt in one day. Use this information to answ
Rufina [12.5K]

Answer:

a. 58.5 g/mol

b. 0.1 mol

Explanation:

a.

The molar mass of Na is 23.0 g/mol. The molar mass of Cl is 35.5 g/mol. The molar mass of NaCl is:

M(Na) + M(Cl) = 23.0 g/mol + 35.5 g/mol = 58.5 g/mol

b. A healthy adult should eat no more than 6 g of salt in one day. The moles corresponding to 6 g of NaCl are:

6 g × (1 mol/58.5 g) = 0.1 mol

7 0
3 years ago
Which scientist was the first to devise the rules of chemical reactions that are explained by modern atomic theory?
valina [46]

Answer:

John Dalton is the correct answer.

Explanation:

3 0
3 years ago
How do I study Chemistry efficiently?
TEA [102]
Review and Study Material Before Going to
Class.

Seek Understanding.

Take Good Notes.

Practice Daily.

Take Advantage of Lab Time.

Use Flashcards.

Use Study Groups.

Break Large Tasks Into Smaller Ones.
5 0
3 years ago
What is the degree of oxidation of a simple substance​​
marissa [1.9K]

Answer: The oxidation state of a free element (uncombined element) is zero. For a simple (monoatomic) ion, the oxidation state is equal to the net charge on the ion. For example, Cl– has an oxidation state of -1. When present in most compounds, hydrogen has an oxidation state of +1 and oxygen an oxidation state of −2.

hope this helps........ Stay safe and have a Merry Christmas!!!!!!!!! :D Explanation:

8 0
2 years ago
Other questions:
  • How many moles are in 15 grams of calcium
    5·2 answers
  • Every substance melts at 0 degrees Celsius and boils at 100 degrees Celsius.
    13·2 answers
  • A 124-mL bubble of hot gas initially at 212 °C and 1.80atm is emitted from an active volcano. What is the final temperature, in
    6·1 answer
  • Which is more prevalent in the food we eat: carbon-12 or carbon-14?
    8·1 answer
  • Explain why you can boil water in a pot without the pot also boiling
    15·1 answer
  • Which type of molecule is shown below?
    8·1 answer
  • How did Rutherford's gold foil experiment show that Thomson's plum pudding model of the atom was
    8·1 answer
  • What is the % dissociation of a solution of acetic acid if at equilibrium the solution has a pH = 4.74 and a pKa = 4.74?
    12·1 answer
  • Molecular compounds are capable of forming multiple covalent bonds. the compound below that contains a triple bond is:
    11·1 answer
  • Which reactions are oxidation-reduction reactions? check all that apply. fes(s) 2hcl(aq) → h2s(g) fecl2(g) agno3(aq) nacl(aq)
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!