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masha68 [24]
3 years ago
9

Objects with higher temperatures:________________.1. emit only shortwave radiation. 2. emit most of their energy in the form of

longwave energy. 3. radiate less total energy than cooler objects radiate. 4. emit more shortwave radiation than cooler objects do.
Chemistry
2 answers:
Strike441 [17]3 years ago
4 0

Answer:

the awnser is 20dggrees

Explanation:

Vikentia [17]3 years ago
3 0
4. emit more shortwave radiation than cooler objects do.
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Balance the following equations:
Brilliant_brown [7]

Answer:

1) 0 C2H4O2 + 0 O2 -> 0 CO2 + 0 H2O (balanced)

2) V2O5 + CaS -> CaO + V2S5

<em>just additional info: V2O5 </em><em>is</em><em> </em><em>divanadium</em><em> </em><em>pentaoxide</em>

LHS (Left hand side)

V: 2

O: 5

Ca: 1

S: 1 x 5 [to balance with the right hand side of the equation]

RHS (Right hand side)

V: 2

O: 1 x 5 [to balance with the left hand side of the equation]

Ca: 1

S: 5

When you balance any elements, you have to balance the whole chemical compound.

Thus,

V2O5 + <em><u>5</u></em> CaS -> <em><u>5</u> CaO</em> + V2S5

LHS CHECK:

V: 2

O: 5

Ca: 5

S: 5

RHS CHECK:

V: 2

O: 5

Ca: 5

S: 5

3) S8 + O2 -> SO2

LHS:

S: 8

O: 2

RHS:

S: 1 x 8 [to balance with LHS]

O: 2

When you balance any elements, you have to balance the whole chemical compound.

S8 + O2 -> <em><u>8</u></em><em><u> </u></em>SO2

When we add 8 to the RHS, it gives us 8S, 16 O.

In order to balance that into the RHS, I need to multiply the O2 by 8, which will give 8(O2) = 16 O particles.

Therefore, <em><u>S8</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>8</u></em><em><u> </u></em><em><u>O2</u></em><em><u> </u></em><em><u>-</u></em><em><u>></u></em><em><u> </u></em><em><u>8</u></em><em><u> </u></em><em><u>SO2</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>final</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>(</u></em><em><u>3</u></em><em><u>)</u></em><em><u>.</u></em>

6 0
3 years ago
If 50 mL of pure acetone is mixed with 450 mL of water, what is the percent by volume of acetone?
slega [8]

Answer:

10%

Explanation:

The percent by volume of acetone is given by the following formula:

% v/v = Volume of acetone / Total Volume * 100%

Now we <u>calculate the total volume of the solution</u>:

Total Volume = Volume of Acetone + Volume of Water

Total Volume = 50 mL + 450 mL = 500 mL

Then we <u>calculate the percent by volume:</u>

% v/v = 50 mL / 500 mL * 100 % = 10%

4 0
3 years ago
How is the sun classified​
pav-90 [236]

Answer: it is classified as a star

Explanation:

The sun is big source of energy but it is still a star

7 0
3 years ago
Read 2 more answers
What is the molarity of a solution made by adding :1.565 moles of PbN03 to 500 mL
jeyben [28]

Answer:

This question is a bit vague. We're not told if 500ml is the volume of the solution and additional info is not given to calculate the volume of pbNo3 being added.

If you solve with 500ml as the volume of solution ... You'll have the answer below.

Molarity=moles of solutes/Volume of solvent(in litres)

moles of solute given=1.565moles

Volume = 500ml. There's 1000ml to a litre. Dividing by 1000ml to convert to Litres... You have 0.5L

Molarity = 1.565/0.5

=3.13M

6 0
3 years ago
1. Which statement is true about oxygen,
sergey [27]

Answer:

they belong to same grop

4 0
2 years ago
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