Answer:
The correct answer is (D) All of the above.
Explanation:
A chemical bond is the attraction force between atoms (covalent bond) or between oppositely charged ions (ionic bond) to form a stable arrangement. In order to get a stable arrangement must be fulfilled the octet rule. This establishes that an atom could share (covalent bond) win or lose (ionic bond) electrons with other atoms till every atom has eight valence electrons. The complete outer shell of valence electrons make elements stable to get a stable noble gas configuration.
Answer:
I do not know. I think there is .as we are the living creatures in this earth. maybe aliens are creatures of other planet or galaxies. I am not scientists to prove it.sorry.
Answer:
Volcanologists use many different kinds of tools including instruments that detect and record earthquakes (seismometers and seimographs), instruments that measure ground deformation (EDM, Leveling, GPS, tilt), instruments that detect and measure volcanic gases (COSPEC), instruments that determine how much lava is moving underground (VLF, EM-31), video and still cameras, infrared cameras, satellite imagers, webcams, etc!
Explanation:
I HOPE IT HELPED
Answer:
(a) adding 0.050 mol of HCl
Explanation:
A buffer is defined as the mixture of a weak acid and its conjugate base -or vice versa-.
In the buffer:
1.0L × (0.10 mol / L) = 0.10 moles of HF -<em>Weak acid-</em>
1.0L × (0.050 mol / L) = 0.050 moles of NaF -<em>Conjugate base-</em>
-The weak acid reacts with bases as NaOH and the conjugate base reacts with acids as HCl-
Thus:
<em>(a) adding 0.050 mol of HCl:</em> The addition of 0.050moles of HCl produce the reaction of 0.050 moles of NaF producing HF. That means after the reaction, all NaF is consumed and you will have in solution just the weak acid <em>destroying the buffer</em>.
(b) adding 0.050 mol of NaOH: The NaOH reacts with HF producing more NaF. Would be consumed just 0.050 moles of HF -remaining 0.050 moles of HF-. Thus, the buffer <em>wouldn't be destroyed</em>.
(c) adding 0.050 mol of NaF: The addition of conjugate base <em>doesn't destroy the buffer</em>
B is the answer
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