Answer:
2
Step-by-step explanation:
the one which is near to x
Sense we are wanting to find <u>
how many were miss</u>
, then, we are practically going to subtract the following:
![\boxed{76-100}= \ \left[\begin{array}{ccc}\bf{24\end{array}\right]](https://tex.z-dn.net/?f=%5Cboxed%7B76-100%7D%3D%20%5C%20%20%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cbf%7B24%5Cend%7Barray%7D%5Cright%5D%20)
So, from this begin understood, we would then combine both the penalties that were shotted, to the onces that weren't.
So, b subtracting these both, we would grab the result, and then smash that with the number of the penalties that were made in.
Your answer:
I'm going to use the substitution method.
4x + 4y = -16
-8x - 6y = -20
4x + 4y = -16
- 4x - 4x
--------------------------
4y = -4x - 16
------ ------ ------
4 4 4
y = -x - 4
-8x - 6(-x - 4) = -20
-8x + 6x + 24 = -20
-2x + 24 = -20
- 24 - 24
----------------------------
-2x = 44
------- -------
2 2
x = 22
4(22) + 4y = -16
88 + 4y = -16
- 88 - 88
------------------------
4y = -104
------ ---------
4 4
y = -26
The answer is (22, -26).
Ith Calculator
41.8 = 100%
215%/100% = 2.15
41.8 x 2.15 = 89.87
Without Calculator
41.8 = 100%
x2
83.6 = 200%
/10
4.18 = 10%
/20
2.09 = 5%
200 + 10 + 5 = 215%
83.6 + 4.18 +2.09 = <span>89.87</span>
Answer:
81 900 000 000 000 is 8.19 × 10¹³
Step-by-step explanation:
Write the first number 8.
Add a decimal point after it: 8.
Now count the number of digits after 8. There are 13 digits.
So, in standard form: 81 900 000 000 000 is 8.19 × 10¹³