Answer:
Option D- frequency of the heterozygous qenotype
Explanation:
In the Hardy-Weinberg equilibrium , 2pq stands for the genotype frequency of heterozygotes (Aa) in a population at the state of equilibrium. dominant homozygotes (AA) is represented by the p-square and q- square represents the recessive homozygotes (aa) frequency. p represents the allele frequency of A Allele and q stands for the allele frequency of the allele a. Summation of the terms gives an equal to 1(100%). The sum of all of these terms is always equal to due to the fact that the 3 frequencies in the equation are the available or possible allele combinations.
Hardy-Weinberg is relevant for it helps us in comparison of a population's actual genetic structure as time goes on along with the genetic structure we are to get if really population was in Hardy-Weinberg equilibrium state that is population was not evolving.
I don’t know but it’s either b or c
Hypothesis: If Plant Food X is used on a tomato plant, then production rate will increase.
experiment: Gather 2 tomato plants of the same height and age. Make two groups, a control group (a tomato plant without use of fertilizer) and an experimental group (a tomato plant with using Plant Food X).
For one week, give each plant the same amount of water, humidity, sunlight, and air temperature. after a week measure the height and number of tomatoes produced. gather the info in a table and compare to hypothesis after one week.
If not parents had a recessive type O allele, they would have a 1/4 or 25% chance of having a child with type O blood
