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Sergeeva-Olga [200]
2 years ago
5

An arts academy requires there to be 6 teachers for every 144 students and 5 tutors for every 40 students. How many students doe

s the academy have per teacher? Per tutor? How many tutors does the academy need if it has 72 students
Mathematics
2 answers:
sleet_krkn [62]2 years ago
7 0

Answer:

3 teachers and 9 tutors

Step-by-step explanation:

Greeley [361]2 years ago
7 0

Answer:

There are 24 students per teacher and 8 students per tutor. If the academy has 72 students, then 9 tutors would be needed.

Step-by-step explanation:

We will start with the question, how many students does the academy have per teacher. To find this, we need to set up the equation. 144 will be the number of students, 6 will be the number of teachers, and x will be the number of students per teacher.

144/6=x

24=x

So, there are 24 students for every teacher.

We could also do this as a ratio. We would do the same thing. We would divide by six to get our answer.

144:6

Make the six one.

24:1

This shows that there are 24 students for every teacher.

Now to find out how many per tutor.

We will do the same thing as before, minus the ratio, though you could still use the ratio. Remember, 40 is the number of students, 5 is the number of tutors, and x is the number of students per tutor.

40\5=x

8=x

So there are 8 students per tutor.

Now we will use this knowledge to solve for how many tutors are needed if the academy has 72 students.

We will set up our equation. 72 will be the students, we will use eight since that is how many students are needed per tutor, and x will be the number of tutors needed.

72/8=x

9=x

So this means that if the academy has 72 students, then it will need 9 tutors.

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3 years ago
Most investors in the stock market are trying to buy a stock at a _______
gogolik [260]

Answer:

d

Step-by-step explanation:

7 0
3 years ago
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ANTONII [103]

The greatest possible number of club members is 7

<em><u>Solution:</u></em>

Given that, local readers’ club has a set of 49 hardback books and a set of 21 paperbacks

Each set can be divided equally among the club members

To find the greatest possible number of club members, we have to find the greatest common factor of 49 and 21

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor.

<em><u>Greatest common factor of 49 and 21:</u></em>

The factors of 21 are: 1, 3, 7, 21

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Then the greatest common factor is 7

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3 years ago
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Ainat [17]

Answer:

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Step-by-step explanation:

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