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2 years ago

(7/2 - 1/3) x (-2) ^2 + 1/2

Mathematics

1 answer:

bagirrra123 [75]2 years ago

3 0

Step-by-step explanation:

please mark me as brainlest

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PLEASE help with these 2 questions<br><br> thank you!

Sergio039 [100]

Download the app photo math help a whole lot

6 0

3 years ago

A cylindrical roller 2.5 m in length, 1.5 m in radius when rolled on a road was found to cover the area of 16500 m2 . How many r

eduard

Answer:

701 revolutions

Step-by-step explanation:

Given: Length= 2.5 m

Radius= 1.5 m

Area covered by roller= 16500 m²

Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.

Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.

Formula; Lateral surface area of cylinder= $2\pi rh$

Considering, π= 3.14

⇒ lateral surface area of cylinder= $2\times 3.14\times 1.5\times 2.5$

⇒ lateral surface area of cylinder= $23.55 \ m^{2}$

∴ Area covered by cylindrical roller in one revolution is 23.55 m²

Next finding total number of revolution to cover 16500 m² area.

Total number of revolution= $\frac{16500}{23.55} = 700.6369 \approx 701$

Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.

8 0

2 years ago

The temperature is -2 deg C . If the temperature rises by 15 deg C what is the new temperature ?

fgiga [73]

Current temperature = -2°C

Rise in temperature = 15°C

New temperature = (-2 + 15)°C = 13°C

5 0

2 years ago

Read 2 more answers

Use a paragraph, flow chart, or two-column proof to prove the angle congruency. Given: ∠ CXY ≅ ∠ BXY

Llana [10]

Answer:

See explanation

Step-by-step explanation:

Consider triangles CAX and BAX. In these triangles,

$\overline{AC}\cong \overline{AB}$ - given
$\angle CAX\cong \angle BAX$ - given
$\overline{AX}\cong \overline{AX}$ - reflexive property

By SAS postulate, $\triangle CAX\cong \triangle BAX$

Congruent triangles have conruent corresponding parts. So,

$\overline{CX}\cong \overline{BX}$

Consider triangles CXY and BXY. In these triangles,

$\overline{CX}\cong \overline{BX}$ - proven
$\angle CXY\cong \angle BXY$ - given
$\overline{XY}\cong \overline{XY}$ - reflexive property

By SAS postulate, $\triangle CXY\cong \triangle BXY$

Congruent triangles have conruent corresponding parts. So,

$\angle XCY\cong \angle XBY$

5 0

2 years ago

X²-y², x²+xy and x² + 2xy + y²<br> plz fast full formula givee

Scorpion4ik [409]

Answer:

Step-by-step explanation:

x²- y² = (x+y) (x-y)

x² + xy = x(x+y)

x² + 2xy + y² = (x+y) (x+y)

3 0

2 years ago