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aliina [53]
3 years ago
8

Perform the following

Chemistry
2 answers:
Sever21 [200]3 years ago
6 0

Answer:

8.97998

Explanation:

True [87]3 years ago
5 0
You use the least amount of sig figs in this case 4 from (3.100).

Answer would be 8.980 after rounding
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One kilogram of water at 100 0C is cooled reversibly to 15 0C. Compute the change in entropy. Specific heat of water is 4190 J/K
mina [271]

Answer:

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Explanation:

If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy (s_{2} - s_{1}), in joules per gram-Kelvin, by the following model:

s_{2} - s_{1} = \int\limits^{T_{2}}_{T_{1}} {\frac{dQ}{T} }

s_{2} - s_{1} = m\cdot c_{w} \cdot \int\limits^{T_{2}}_{T_{1}} {\frac{dT}{T} }

s_{2} - s_{1} = m\cdot c_{w} \cdot \ln \frac{T_{2}}{T_{1}} (1)

Where:

m - Mass, in kilograms.

c_{w} - Specific heat of water, in joules per kilogram-Kelvin.

T_{1}, T_{2} - Initial and final temperatures of water, in Kelvin.

If we know that m = 1\,kg, c_{w} = 4190\,\frac{J}{kg\cdot K}, T_{1} = 373.15\,K and T_{2} = 288.15\,K, then the change in entropy for the entire process is:

s_{2} - s_{1} = (1\,kg) \cdot \left(4190\,\frac{J}{kg\cdot K} \right)\cdot \ln \frac{288.15\,K}{373.15\,K}

s_{2} - s_{1} = -1083.112\,\frac{J}{kg\cdot K}

The change in entropy is -1083.112 joules per kilogram-Kelvin.

7 0
3 years ago
Which type of star has the lowest density?
julsineya [31]
The white dwarf has the lowest density of the stars listed. Hope this helps and have a nice day!
8 0
4 years ago
Read 2 more answers
Provide the reagents necessary to carry out the following conversion.
Alika [10]

Answer:

see explanation below

Explanation:

First, you are not providing the reaction to do the conversion. However, in picture 1, I attached a reaction that match perfectly with the description of this question, so I hope it could be.

Now picture 2, shows you the correct steps of conversion, now let me explain a little here the mechanism:

The first step in all options is the same. Those reagents works to do an oxidation of the methyl group to a carboxilic acid, and then, we transform toluene into benzoic acid. Now the second step in the first option involves Cl2 in light, and this only works to do halide alkylation in acyclic chains, so this would not work in the reaction to get the final product. In option 2, we have Cl2/FeCl3, and this will promote a friedel craft alkylation, and Chlorine will go to the para position of the ring, so we can exclude this option. However option 3 and 4 uses SOCl2, and this is often used to convert the hydroxile group of a molecule into an halide, so these two options works in the second step.

Now, for the step 3, option 4 uses grignard reagent with (CH3CH2)2CH2MgBr as reagent, but this will only form a larger chain and the CH3CH2 will not break, so, this option is discarted, and finally option 3 will be the correct one. Picture 2 shows you every step.

6 0
3 years ago
I need help I don’t understand it and I need it done before the end of today
amm1812

Answer:

May be trial 2..................

5 0
3 years ago
Read 2 more answers
A 9.35g sample of a solid was placed in a 15.00mL flask. The remaining volume was filled with Benzene in which the solid is inso
NikAS [45]
The problem ask to calculate the density of the solid if it has a mass of 9.35g and is place in a 15ml flask. Base on my calculation and further formulation about the density of the two, by subtracting the density of the Benzene, the solid has a density of 1.59g/ml. I hope this would help 
3 0
3 years ago
Read 2 more answers
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