Question

15.1 L N2 at 25 °C and 125 kPa and 44.3 L O2 at 25 °C and 125 kPa were transferred to a tank with a volume of 6.25 L. What is the total pressure at 51 °C?

Answer 1

Answer:

The total pressure of the mixture in the tank of volume 6.25 litres at 51°C  is 1291.85 kPa.

Explanation:

For N2,

                Pressure(P₁)=125 kPa

                  Volume(V₁)=15·1 L

                Temperature (T₁)=25°C=25+273 K=298 K

Similarly, for Oxygen,

                   Pressure(P₂)= 125 kPa

                   Volume(V₂)= 44.3 L

                  Temperature(T₂)=25°C= 298 K

Then, for the mixture,

              Volumeof the mixture( V)= 6.25 L

                                     Pressure(P)=?

                Temperature (T)= 51°C = 51+273 K=324 K

Then, By Combined gas laws,

                                 $\frac{P_{1} V_{1} }{T_{1} } +\frac{P_{2} V_{2} }{T_{2} } =\frac{PV}{T}$

                      or, $\frac{15.1*125}{298} +\frac{44.3*125}{298} =\frac{P*6.25}{324}$

                     or, $6.34+18.58=\frac{P*6.25}{324}$

                     or, $P=\frac{24.92*324}{6.25}$

                        ∴P=1291.85 kPa

So the total pressure of the mixture in the tank of volume 6.25 litres at 51°C  is 1291.85 kPa.