If the two sides with length 3 and 4 are the two legs, then the missing side, i.e. the hypotenuse, is indeed 5.
But it could also be the case that 4 is the hypotenuse and 3 is one of the legs. In this case, the missing side is the other leg, so we calculate it using
So, a right triangle with legs 
and 3 has an hypotenuse of 4.
Answer:
The answer is 0.56 the 6 is repeating
Step-by-step explanation:
Answer:
Perimeter = 317 m
Step-by-step explanation:
Given track is a composite figure having two semicircles and one rectangle.
Perimeter of the given track = Circumference of two semicircles + 2(length of the rectangle)
Circumference of one semicircle = πr [where 'r' = radius of the semicircle]
= 25π
= 25 × 3.14
= 78.5 m
Length of the rectangle = 80 m
Perimeter of the track = 2(78.5) + 2(80)
= 157 + 160
= 317 m
Therefore, perimeter of the track = 317 m
This is a parabola which opens upwards and the directrix will be of the form
y = k
the general form is
4p(y - k) = (x - h)^2 we have:-
1/4(y + 3) = (x - 2)^2
so the vertex is at (2, -3)
4p = 1/4 so p = 1/16
so the focus will be at (2 , -2 15/16)
and directrix is y = -3 1/16
Answer:
By making ‘a’ the subject, I believe you mean isolate the variable ‘a’.
1/a - 1/b = 1/c : add 1/b to both sides
1/a = 1/b + 1/c : combine the unlike fractions by finding a common denominator, bc is the common denominator
1/a = (1/b)(c/c) + (1/c)(b/b) : simplify
1/a = (c/bc) + (b/bc) : add numerators only, because the denominators match
1/a = (c + b)/bc : multiply both sides by a
1 = (a)[(c + b)/bc] : multiply both sides by the reciprocal of [(c + b)/bc] which is [bc/(b + c)]
1[bc/(b + c)] = a
a = bc/(b + c)
This will not work if c = -b, because then you would be dividing by zero.
Example: 1/2 - 1/3 = 1/6 a = 2, b = 3 c= 6
a = bc/(b + c) => 2 = (3 x 6)/(3 + 6) => 2 = 18/9 => 2 = 2.
Step-by-step explanation:
