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hoa [83]
3 years ago
13

50 J of work was done on a system, as a result of which 29 J of heat energy was removed from it. How would this affect the inter

nal energy of the system? A) The internal energy of the system would decrease by 21 J. B) The internal energy of the system would increase by 21 J. C) The internal energy of the system would decrease by 79 J. D) The internal energy of the system would increase by 79 J.
Chemistry
2 answers:
cricket20 [7]3 years ago
3 0
  • Work done=50J
  • Heat removed=29J

Now

\\ \sf\longmapsto \Delta E=50-29

\\ \sf\longmapsto \Delta E=21J

  • Hence the internal energy would increase by 21J

Option B is correct

sergeinik [125]3 years ago
3 0

Answer:

i would say a because it makes sense i mean so does b but i think it is a or b but i think a

Explanation:

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3 years ago
What amount of acid is esterified if a mixture consist initially of 1.0mole of ethanoic acid,1.0mole of ethanol and 1.0mole of w
ale4655 [162]

Answer:

0.54 mole

Explanation:

                                     CH3COOH    CH3CH2OH   CH3COOCH2CH3    H2O​

Initial concentration   1.0 mole         1.0 mole                0 mole                  1.0mol

Change                          - x                   - x                      + x                          + x  

Equilibrium                   (1.0 - x)          (1.0 - x)                   x                       (1.0 + x)

K = [CH3COOCH2CH3]*[H2O​]/[CH3COOH]*[CH3CH2OH]

x*(1.0+x)/(1.0-x)(1.0-x) = 4.0

x+x²=4*(1-x)²

x+x² = 4(1² - 2x + x²)

x + x² = 4 - 8x + 4x²

4 - 8x + 4x²- x² - x= 0

3x² - 9x + 4 = 0

x=2.5 , x=0.54

2.5 mole of acid cannot be esterified, because there is only 1.0 mole of acid,

so answer is 0.54 mole.

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i believe the whole number would be this but usually i round to the second decimal point, i dont know if you could do that in chemistry tho

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