1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hoa [83]
3 years ago
13

50 J of work was done on a system, as a result of which 29 J of heat energy was removed from it. How would this affect the inter

nal energy of the system? A) The internal energy of the system would decrease by 21 J. B) The internal energy of the system would increase by 21 J. C) The internal energy of the system would decrease by 79 J. D) The internal energy of the system would increase by 79 J.
Chemistry
2 answers:
cricket20 [7]3 years ago
3 0
  • Work done=50J
  • Heat removed=29J

Now

\\ \sf\longmapsto \Delta E=50-29

\\ \sf\longmapsto \Delta E=21J

  • Hence the internal energy would increase by 21J

Option B is correct

sergeinik [125]3 years ago
3 0

Answer:

i would say a because it makes sense i mean so does b but i think it is a or b but i think a

Explanation:

You might be interested in
When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin
loris [4]

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point

K_f = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality =\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9

8.2^0C=1\times K_f\times 1.9

K_f=4.32^0C/m

Now Depression in freezing point for sodium chloride is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=20.0^0C = Depression in freezing point

K_f = freezing point constant  

m= molality = \frac{136g\times 1000}{950g\times 58.5g/mol}=2.45

20.0^0C=i\times 4.32^0C\times 2.45

i=1.9

Thus vant hoff factor for sodium chloride in X is 1.9

3 0
3 years ago
How did Bohr refine the model of the atom? How did Bohr refine the model of the atom? He developed electrochemistry. He discover
BartSMP [9]

Answer:

He developed the concept of concentric electron energy levels

Explanation:

Before Bohr's model, Rutherford's model was proposed. This model explains most of the properties of the atom but failed to explain the stability of the atom.

As per Rutherford's model, electrons revolve around the nucleus in the orbit.

But revolving electron in their orbit around nucleus would give up energy and so gradually move towards the nucleus and therefore, eventually collapse.

Bohr's proposed that the electrons around the nucleus move orbit of fixed energy called "stationary states". Electrons in these stationary states  do not radiate energy.

Therefore, proposal of concentric electron energy levels refine the atomic models.

5 0
3 years ago
Suppose a 0.025M aqueous solution of sulfuric acid (H2SO4) is prepared. Calculate the equilibrium molarity of SO4−2. You'll find
FromTheMoon [43]

<u>Answer:</u> The concentration of SO_4^{2-} at equilibrium is 0.00608 M

<u>Explanation:</u>

As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.

In the second dissociation, the ions will remain in equilibrium.

We are given:

Concentration of sulfuric acid = 0.025 M

Equation for the first dissociation of sulfuric acid:

       H_2SO_4(aq.)\rightarrow H^+(aq.)+HSO_4^-(aq.)

            0.025          0.025       0.025

Equation for the second dissociation of sulfuric acid:

                    HSO_4^-(aq.)\rightarrow H^+(aq.)+SO_4^{2-}(aq.)

<u>Initial:</u>            0.025            0.025      

<u>At eqllm:</u>      0.025-x          0.025+x        x

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H^+][SO_4^{2-}]}{[HSO_4^-]}

We know that:

Ka_2\text{ for }H_2SO_4=0.01

Putting values in above equation, we get:

0.01=\frac{(0.025+x)\times x}{(0.025-x)}\\\\x=-0.0411,0.00608

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of sulfate ion = x = 0.00608 M

Hence, the concentration of SO_4^{2-} at equilibrium is 0.00608 M

4 0
3 years ago
Water is always subject to the law of
dimulka [17.4K]

Answer:

motion

Explanation:

i just know things

5 0
3 years ago
I need help with this question
KiRa [710]
A challenge they could face is that the plants are not used to the climate in the new area . (sorry if it’s wrong)
5 0
3 years ago
Other questions:
  • Which reaction is an example of an acid-base reaction? Which reaction is an example of an acid-base reaction?
    5·1 answer
  • A solution is prepared by dissolving 40.0 g of sucrose, in 250 g of water at 25°C. What is the vapor pressure of the solution if
    12·2 answers
  • What mass of NH3 can be made from 35.0g of N2?
    9·2 answers
  • Which one of the following is an attribute for an extracting solvent?
    13·1 answer
  • If there are 77 electrons in a neutral atom then how many protons will be in the same atom?
    8·1 answer
  • Hey what's the value of pi till<br>5 digits after decimal​
    14·2 answers
  • When nitrogen gas (N2) reacts with hydrogen gas(H) ammonia gas (NH3) is formed. How many grams of hydrogen gas are required to r
    12·1 answer
  • 3. What is the primary consumer in the following food chain, sun - tomato plant - tomato worm - wasp?
    6·2 answers
  • Why does D2O <br>have a higher boiling point than H2O ​
    12·2 answers
  • What atomic number 15 protons and 10 neutrons and 13 electrons
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!