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hoa [83]
3 years ago
13

50 J of work was done on a system, as a result of which 29 J of heat energy was removed from it. How would this affect the inter

nal energy of the system? A) The internal energy of the system would decrease by 21 J. B) The internal energy of the system would increase by 21 J. C) The internal energy of the system would decrease by 79 J. D) The internal energy of the system would increase by 79 J.
Chemistry
2 answers:
cricket20 [7]3 years ago
3 0
  • Work done=50J
  • Heat removed=29J

Now

\\ \sf\longmapsto \Delta E=50-29

\\ \sf\longmapsto \Delta E=21J

  • Hence the internal energy would increase by 21J

Option B is correct

sergeinik [125]3 years ago
3 0

Answer:

i would say a because it makes sense i mean so does b but i think it is a or b but i think a

Explanation:

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Answer:

B and C

Explanation:

When we have to do a buffer solution we always have to choose the reaction that has the <u>pKa closer to the desired pH value</u>. When we find the pKa values we will obtain:

pKa_1=-Log[6.9x10^-^3]=2.16

pKa_2=-Log[6.2x10^-^8]=7.20

pKa_3=-Log[4.8x10^-^13]=12.31

The closer value is pKa2 with a value of 7.2. Therefore we have to use the second reaction. In which  H_2PO_4^-^1 is the <u>acid</u> and HPO_4^-^2 is the <u>base</u>. Therefore the answer for the first question is B and the answer for the second question is C.

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C

a mountain range will form

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3.5 grams is equivalent to how many kilograms? 3500 kg 35,000 kg 0.35 kg 0.0035 kg
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