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hoa [83]
3 years ago
13

50 J of work was done on a system, as a result of which 29 J of heat energy was removed from it. How would this affect the inter

nal energy of the system? A) The internal energy of the system would decrease by 21 J. B) The internal energy of the system would increase by 21 J. C) The internal energy of the system would decrease by 79 J. D) The internal energy of the system would increase by 79 J.
Chemistry
2 answers:
cricket20 [7]3 years ago
3 0
  • Work done=50J
  • Heat removed=29J

Now

\\ \sf\longmapsto \Delta E=50-29

\\ \sf\longmapsto \Delta E=21J

  • Hence the internal energy would increase by 21J

Option B is correct

sergeinik [125]3 years ago
3 0

Answer:

i would say a because it makes sense i mean so does b but i think it is a or b but i think a

Explanation:

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A 100.0-mL sample of 1.00 M NaOH is mixed with 50.0 mL of 1.00 M H2SO4 in a large Styrofoam coffee cup calorimeter fitted with a
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Answer:

THE ENTHALPY CHANGE IN KJ/MOLE IS +114 KJ/MOLE.

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Total mass = density * volume

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