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lesantik [10]
3 years ago
15

Use what you know about the orbits of Earth and the moon to sort the phrases into the correct Category.

Chemistry
1 answer:
Kobotan [32]3 years ago
8 0

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Astrophysics.

Let's categorize them eventually ==>

1.) Earth ==> 1.) travels around the Sun

2.) takes 365.25 days .

2.) Moon ===> 1.) travels around the Earth

2.) Takes 27.3 days.

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The metric unit for volume is the? <br><br> A. pound<br> B.quart<br> C.liter<br> D.gallon
Vladimir [108]
I believe it is liter.
5 0
3 years ago
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When a solution of NaI reacts with a solution of AgNO3, what is the net ionic equation?
Leni [432]

Answer:

Ag⁺(aq) + I⁻(aq) → AgI(s)

Explanation:

Net ionic equation is a way to write a chemical equation in which you are listing only the species that are participating in the reaction.

In the reaction:

AgNO₃(aq) + NaI(aq) → AgI(s) + NaNO₃(aq).

The ionic equation is:

Ag⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + I⁻(aq) → AgI(s) + Na⁺(aq) + NO₃⁻(aq).

Now, listing only the species that are participating in the reaction:

<h3>Ag⁺(aq) + I⁻(aq) → AgI(s)</h3>

3 0
3 years ago
The volume of 0.6305 kg of a liquid is 0.430 L. What is its density in g/mL
motikmotik

Answer: 1.466 g/mL

Explanation:

\frac{0.6305 \text{kg}}{0.430 \text{L}} \cdot \frac{1000 \text{g}}{1 \text{kg}} \cdot  \frac{1 \text{L}}{1000 \text{mL}} = 1.466 \,\frac{\text{g}}{\text{mL}}

6 0
2 years ago
A 2.0 L container of nitrogen gas had a pressure of 3.2 atm. What volume would be necessary to decrease the pressure to 1.0 atm
beks73 [17]

Answer:

6.4 L

Explanation:

When all other variables are held constant, you can use Boyle's Law to find the missing volume:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the theoretical volume by plugging the given values into the equation and simplifying.

P₁ = 3.2 atm                      P₂ = 1.0 atm

V₁ = 2.0 L                          V₂ = ? L

P₁V₁ = P₂V₂                                                    <----- Boyle's Law

(3.2 atm)(2.0 L) = (1.0 atm)V₂                        <----- Insert values

6.4 = (1.0 atm)V₂                                           <----- Simplify left side

6.4 = V₂                                                        <----- Divide both sides by 1.0

6 0
2 years ago
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a_sh-v [17]
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