Water is made of 2 hydrogen and 1 oxygen atoms. The molecular weight for water should be 1+ 1+ 16= 18. Then the amount of water molecule in 11.4 gram of water should be: 11.4g/18= 0.63 moles.
Since 1 water means 2 hydrogen atoms, then the amount of hydrogen atom should be: 2/1 * 0.63= 1.26 moles of hydrogen
Answer:
Explanation:
H = 1
C = 12
O = 16
Acetylene, HC≡CH = 2+24 = 26
H2O = 2 + 16 = 18
In XS oxygen, one HC≡CH yields one H2O
26 g HC≡CH ==> 18 g H2O
2000 g HC≡CH ==> 2000*18/26 g H2O = 1384.6154 g H2O
Answer:
RxN: Na₂CO₃ (aq) + 2HCl (aq) → 2NaCl (aq) + H₂CO₃ (aq)
NIE: n/a
Explanation:
Step 1: Predict (Double Replacement)
Na₂CO₃ (aq) + HCl (aq) → NaCl (aq) + H₂CO₃ (aq)
Step 2: Balance
Na₂CO₃ (aq) + 2HCl (aq) → 2NaCl (aq) + H₂CO₃ (aq)
Step 3: Write Total Ionic Equation
2Na⁺ (aq) + CO₃²⁻ (aq) + 2H⁺ (aq) + 2Cl⁻ (aq) → 2Na⁺ (aq) + 2Cl⁻ (aq) + 2H⁺ (aq) + CO₃²⁻ (aq)
Step 4: Remove Spectator Ions
- Na⁺
- CO₃²⁻
- H⁺
- Cl⁻
Step 5: Write Net Ionic Equation
None.
Answer:
The answer to your question is 1.40 moles of N₂O
Explanation:
Balanced equation
NH₄NO₃ ⇒ N₂O + 2 H₂O
2 -------- N ---------- 2
4 ------- H ---------- 4
3 ------- O ---------- 3
Process
1.- From the balanced equation, we know that 1 mol of NH₄NO₃ produces 1 mol of N₂O so, we use proportions to find the number of moles produced when 1.40 moles of NH₄NO₃ react.
1 mol of NH₄NO₃ ------------- 1 mol of N₂O
1.40 moles -------------- x
x = (1.40 x 1) / 1
x = 1.40 moles of N₂O are produced
HCH bond angle is ~110 degrees.
