The process of converting a liquid into a solid is called (4 points)

50.0 mL of a solution of HCl is combined with 100.0 mL of 1.05M NaOH in a calorimeter. The reaction mixture is initially at 22.4

VikaD [51]

Answer:

2.1 M is the molarity of the HCl solution.

Explanation:

$HCl+NaOH\rightarrow H_2O+NaCl$

Molarity of HCl solution = $M_1=?$

Volume of HCl solution = $V_1=50.0mL$

Ionizable hydrogen ions in HCl = $n_1=1$

Molarity of NaOH solution = $M_2=1.05 M$

Volume of NaOH solution = $V_2=100.0 mL$

Ionizable hydroxide ions in NaOH = $n_2=1$

$n_1M_1V_1=n_2M_2V_2$ (neutralization )

$M_1=\frac{M_2V_2}{V_1}=\frac{1.05M\times 100.0 mL}{50.0 mL}$

$M_1=2.1 M$

2.1 M is the molarity of the HCl solution.

3 0

2 years ago

1.Chlorobenzene, C6H5Cl, is used in the production of chemicals such as aspirin and dyes. One way that chlorobenzene is prepared

miv72 [106K]

Answer:

$m_{C_6H_5Cl}=65.7gC_6H_5Cl$

Explanation:

Hello!

In this case, according to the given balanced chemical reaction:

$C_6H_6 (l) + Cl_2 (g) \rightarrow C_6H_5Cl (s) + HCl (g)$

We can see there is 1:1 between benzene and chlorobenzene as the relavant product; thus, since the molar mass of benzene is 78.11 g/mol and that of chlorobenzene is 112.55 g/mol, the theoretical yield for this reaction turns out:

$m_{C_6H_5Cl}=45.6gC_6H_6*\frac{1molC_6H_6}{78.11gC_6H_6 }*\frac{1molC_6H_5Cl}{1molC_6H_6}*\frac{112.55gC_6H_5Cl}{1molC_6H_5Cl} \\\\m_{C_6H_5Cl}=65.7gC_6H_5Cl$

Best regards!

8 0

2 years ago

Use the drop-down menus to classify each of the following as an addition, substitution, elimination, or

OLga [1]

Answer:

CH3CHO+H2O → CH3OCH3 - addition

CH,CICH CI + Zn → C2H4 + ZnCl2 - elimination

CH3CH3Br + OH – CH3CH3OH + Br - substitution

2CH2COOH >>(CH3CO)20 + H20 - condensation

Explanation:

An addition reaction is a reaction in which a specie is added across the double bond as we can see in CH3CHO+H2O → CH3OCH3.

In an elimination reaction, a small molecule is lost from a saturated compound to form the corresponding unsaturated compound as in CH,CICH CI + Zn → C2H4 + ZnCl2

In a substitution reaction, a chemical moiety replaces another in a molecule as in; CH3CH3Br + OH – CH3CH3OH + Br .

A condensation reaction is in which two molecules are joined together to form a bigger molecule as in; 2CH2COOH >>(CH3CO)20 + H20.

4 0

2 years ago

What is responsible for the blue sky?

andreev551 [17]

Answer:

well for me it's

Explanation:

The reflection of the seas

7 0

2 years ago

Read 2 more answers

What volumes of 0.200 M HCOOH and 2.00 M NaOH would make 500. mL of a buffer with the same pH as one made from 475 mL of 0.200 M

Fed [463]

36 ml of NaOh and 464 ml of HCOOH would be enough to form 500 ml of a buffer with the same pH as the buffer made with benzoic acid and NaOH.

What is benzoic acid found in?

Some natural sources of benzoic acid include: Fruits: Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
Spices: Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.

Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.

Amount of moles of NaOH -2 × 0.025 = 0.05 mol

Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol

In this case, we can calculate the pH produced by the buffer of these two reagents, as follows

$pH = pKa + log\frac{base}{acid}$