Question

upon landing, a rightward-moving airplane accelerates from 72m/s to 8m/s in 5.3 s. Determine the magnitude kf the average acceleration of the airplane in m/s/s.Enter a numerical answer, accurate to the hundredths place

Answer 1

The kinematics and Newton's second law allow to find the answers for the acceleration and the force are:

• The deceleration of the plane a = - 12 m / s²

• The applied force is F = -960 kN

The kinematics studies the movement of bodies, in which case they indicate the initial velocity v₀ = 72 m/s, the final velocity v = 8 m/s and the time t = 5.3 s, asking how much the acceleration is worth.

            v = v₀ - a t

            a = $\frac{v-v_o}{t}$

Let's calculate

           a = $\frac{8-72}{5.3}$

           a = -12 m / s²

The negative sign indicates that the acceleration is opposite to the velocity.

The second part of the exercise asks for the magnitude of the force that creates this acceleration, for this we use Newton's second law which states that the force is directly proportional to the mass and the acceleration of the body

            F = m a

Where F is the force, m the mass and the acceleration

           F = m ( -12)

           F = -12 m  [N]

In order to finish the problem we must have the mass of the body, suppose the mass of the plane is m = 80 10³ kg

Let's calculate the force

            F = -12 80 10³

            F = -960 10³ N

They request the answer in kilo newton let's reduce

             F = -960 kN

The negative sign indicates that the force and acceleration go in the same direction

In conclusion using kinematics and Newton's second law we can find the answers for the acceleration and the force are

       a = - 12 m / s²

       F = -960 kN

Learn more here:  brainly.com/question/15378807