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attashe74 [19]
3 years ago
8

Plz help if you can!!!

Chemistry
1 answer:
Shkiper50 [21]3 years ago
5 0

Answer:

The answer to your question is: A and C are elements. Substance D is a compound.

Explanation:

We know that A and C cannot be broken down into anything simpler then we conclude  that they are elements.

Also know that B is composed by A and D and are not chemically bonded, so we conclude that B is a mixture

Finally, D can be decomposed into A and C, so it's a compound.

The only possible answer is the last one.

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Do atoms lend and borrow electrons from inner shells
zaharov [31]
False. They don't borrow electrons at all. They already have their respective electron affinities. This is called as electronegativity, and it's an occurence where it already has its own from its actual structure. It never borrows any electrons at all.
4 0
3 years ago
The combustion of 1.5011.501 g of fructose, C6H12O6(s)C6H12O6(s) , in a bomb calorimeter with a heat capacity of 5.205.20 kJ/°C
avanturin [10]

Answer : The internal energy change is -2805.8 kJ/mol

Explanation :

First we have to calculate the heat gained by the calorimeter.

q=c\times (T_{final}-T_{initial})

where,

q = heat gained = ?

c = specific heat = 5.20kJ/^oC

T_{final} = final temperature = 27.43^oC

T_{initial} = initial temperature = 22.93^oC

Now put all the given values in the above formula, we get:

q=5.20kJ/^oC\times (27.43-22.93)^oC

q=23.4kJ

Now we have to calculate the enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat gained = 23.4 kJ

n = number of moles fructose = \frac{\text{Mass of fructose}}{\text{Molar mass of fructose}}=\frac{1.501g}{180g/mol}=0.00834mole

\Delta H=-\frac{23.4kJ}{0.00834mole}=-2805.8kJ/mole

Therefore, the enthalpy change during the reaction is -2805.8 kJ/mole

Now we have to calculate the internal energy change for the combustion of 1.501 g of fructose.

Formula used :

\Delta H=\Delta U+\Delta n_gRT

or,

\Delta U=\Delta H-\Delta n_gRT

where,

\Delta H = change in enthalpy = -2805.8kJ/mol

\Delta U = change in internal energy = ?

\Delta n_g = change in moles = 0   (from the reaction)

R = gas constant = 8.314 J/mol.K

T = temperature = 27.43^oC=273+27.43=300.43K

Now put all the given values in the above formula, we get:

\Delta U=\Delta H-\Delta n_gRT

\Delta U=(-2805.8kJ/mol)-[0mol\times 8.314J/mol.K\times 300.43K

\Delta U=-2805.8kJ/mol-0

\Delta U=-2805.8kJ/mol

Therefore, the internal energy change is -2805.8 kJ/mol

5 0
3 years ago
What is the purpose of the underlined sentence in the passage?
gregori [183]

Answer:

C

Explanation:

5 0
3 years ago
JWL 3.R 1.096776 x 107 m) L) 384.6 nm C) 683.8 nm D) 1282 nm E) >1500 nm Ans: D According to the Rydberg equation, the line w
sesenic [268]

Answer:

91.2 nm

Explanation:

The Rydberg equation is given by the formula

     1/ λ  = Rh ( 1/ n₁² - 1/ n₂²)

where

λ is the wavelength

Rh is Rydberg constant

and n₁ and n₂ are the energy levels of the transion.

We can see from this equation that the wavelength is inversely proportional to the difference of the squares of the inverse of the quantum numbers n₁ and n₂. It follows then that the smallest wavelength will be given when the the transitions are between the greatest separation between n₁ and n₂ whicg occurs when n1= 1 and n₂= ∞ , that is the greater the separation in energy levels the shorter the wavelength.

Substituting for n₁ and n₂ and solving for λ :

  1/λ = 1.0974 x 10⁷ m⁻¹ x ( 1/1² -1/ ∞²)  =  1.0974 x 10⁷ m⁻¹ x ( 1/1² - 0) =

  λ = 1/1.0974 x 10⁷ m = 9.1 x 10⁻8 m = 91.2 nm

4 0
3 years ago
Why does the particle of water at 0 degree celcius have more energy as cimparrd to the particles in ice at the same temperature?
jekas [21]
There is Kinetic energy involved in the state something is in. The molecules in a liquid are moving around quicker than those in a solid. 

That's one reason.

The ice requires energy to melt. Bonds must be broken to get from a solid to a liquid.

5 0
3 years ago
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