Answer:
V = m
d = 14 830 g × 1
c
m
³
19.32
g = 767.6 cm³
Answer:
B
Explanation:
Because the sharpener is attached to an electrical outlet
<u>Answer:</u> The mass of iron (II) oxide that must be used in the reaction is 30.37
<u>Explanation:</u>
The given chemical reaction follows:
By Stoichiometry of the reaction:
When 635 kJ of energy is released, 6 moles of iron (II) oxide is reacted.
So, when 44.7 kJ of energy is released, 
of iron (II) oxide is reacted.
Now, calculating the mass of iron (II) oxide by using the equation:
Moles of iron (II) oxide = 0.423 moles
Molar mass of iron (II) oxide = 71.8 g/mol
Putting values in above equation, we get:
Hence, the mass of iron (II) oxide that must be used in the reaction is 30.37
Answer:
Two
Explanation:
Elements in group 16 wants to bond with elements in group IIA, the group of alkaline earth metals.
- The bonding will make it easier for them complete their octet.
- Elements in group 16 has 6 valence electrons.
- To have a complete octet, they require 2 more electrons.
- Group II elements are willing donors as they are metals.
- For Group II elements to fill their octets, they must lose two electrons.
- So the willingness of group II elements to lose two electrons and the readiness for group 16 elements to gain the electrons makes the desire one another.
