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KonstantinChe [14]
3 years ago
13

What is the mass of a 1.2N book?

Physics
2 answers:
const2013 [10]3 years ago
7 0

2.8 kg .............is the mass of a 1.2 N book.

7nadin3 [17]3 years ago
5 0

Explanation:

force= mass*gravity

1.2N=m*10

1.2/10=m

m=0.12

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A chocolate chip cookie can be separated by physical means, and it is not the same throughout. How would you classify it?
Oliga [24]
I believe it is a heterogenous mixture

5 0
4 years ago
26 people is to be airconditioned. A person in the classroom typically dissipates heat at a rate of 360 kJ/h. The room is lit wi
miv72 [106K]

Answer:

The capacity of refrigeration =5.35kw

Explanation:

Total people in classroom =26

One person dissipates =360kj/h

So 26 person will dissipates =360 × 26

                                                  =2.6kw

15 light bulb with 40w each

Total heat dissipates     15×40 =600

                                                =0.6kw

Fan will dissipate  =200w

                             =0.2kw

Room gain air at a rate of =200kg/h

Warm air enthalpy =10kj/kg

Total heat coming with warm air = 200×10

                                                         0.555kw

Heat coming from window walls =5000kj/h

                                                       =5000/3600=  1.388kw

Total heat coming in the room =2.6+0.6+0.2+0.55+1.388

                                                   =5.35kw

To maintain room at steady temperature

Heat should be removed at constant rate

Energy balance =energy in/energy out

Capacity of refrigeration =5.35kw

7 0
3 years ago
A 3.91 kg cart is moving at 5.7 m/s when it collides with a 4 kg cart which was at rest. They collide and stick together.
Nesterboy [21]

Answer:

<em>The velocity after the collision is 2.82 m/s</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is  

P=mv.  

If we have a system of two bodies, then the total momentum is the sum of the individual momentums:

P=m_1v_1+m_2v_2

If a collision occurs and the velocities change to v', the final momentum is:

P'=m_1v'_1+m_2v'_2

Since the total momentum is conserved, then:

P = P'

Or, equivalently:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

If both masses stick together after the collision at a common speed v', then:

m_1v_1+m_2v_2=(m_1+m_2)v'

The common velocity after this situation is:

\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}

There is an m1=3.91 kg car moving at v1=5.7 m/s that collides with an m2=4 kg cart that was at rest v2=0.

After the collision, both cars stick together. Let's compute the common speed after that:

\displaystyle v'=\frac{3.91*5.7+4*0}{3.91+4}

\displaystyle v'=\frac{22.287}{7.91}

\boxed{v' = 2.82\ m/s}

The velocity after the collision is 2.82 m/s

6 0
3 years ago
QUESTION 1
Molodets [167]
Question 1: C Question 2: B, Hope this Helps!
3 0
3 years ago
1.) A projectile is launched at 32.1 m/s and 52.6 º above the horizontal. Determine the:
Mandarinka [93]

Answer:

a.) Maximum height of the projectile. =32.5m

b.) The time it takes to reach the maximum height=2.6s

c.) Time of flight=2.6s

d.) Range=99.5m

Explanation:

5 0
3 years ago
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