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KonstantinChe [14]
2 years ago
13

What is the mass of a 1.2N book?

Physics
2 answers:
const2013 [10]2 years ago
7 0

2.8 kg .............is the mass of a 1.2 N book.

7nadin3 [17]2 years ago
5 0

Explanation:

force= mass*gravity

1.2N=m*10

1.2/10=m

m=0.12

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Electromagnetic waves do require a medium to travel.<br><br> True<br> False
pshichka [43]

Answer:

The Answer is false

Explanation:

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

8 0
3 years ago
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An object of mass m travelling at velocity u collides with an identical stationary object of mass m. After collision, both objec
frutty [35]
Hope this helps! If in need of clarification, feel free to ask :)

6 0
3 years ago
What is the mass of a cannonball if the force a force of 2500 N gives the cannonball an acceleration of 200 m/s^2??
vampirchik [111]

The answer is a.12.5kg because i just did the test and it was correct.

hope this helps


5 0
3 years ago
A particle is confined to the x-axis between x = 0 and x = 1 nm. The potential energy U = 0 inside this region and U is infinite
DiKsa [7]

Answer:

Explanation:

According to heisenberg uncertainty Principle

Δx Δp ≥ h / 4π , where Δx  is uncertainty in position , Δp is uncertainty in momentum .

Given

Δx = 1 nm

Δp ≥ h /1nm x  4π

≥ 6.6 x 10⁻³⁴ / 10⁻⁹ x  4 π

≥  . 5254 x ⁻²⁵

h / λ ≥  . 5254 x ⁻²⁵

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12.56 x 10⁻⁹ ≥ λ  

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6 0
3 years ago
An inattentive driver is traveling 18.0 m/s when he notices a red light ahead. his car is capable of decelerating at a rate of 3
ryzh [129]

Speed of the car given initially

v = 18 m/s

deceleration of the car after applying brakes will be

a = 3.35 m/s^2

Reaction time of the driver = 0.200 s

Now when he see the red light distance covered by the till he start pressing the brakes

d_1 = v* t

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Now after applying brakes the distance covered by the car before it stops is given by kinematics equation

v_f^2 - v_i^2 = 2 a s

here

vi = 18 m/s

vf = 0

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0^2 - 18^2 = 2*(-3.35)(s)

s = 48.35 m

So total distance after which car will stop is

d = d_1 + d_2

d = 48.35 + 3.6 = 51.95 m

So car will not stop before the intersection as it is at distance 20 m

3 0
3 years ago
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