A chocolate chip cookie can be separated by physical means, and it is not the same throughout. How would you classify it?

Water flows through a 4.0-cm-diameter horizontal pipe at a speed of 1.3 m/s. The pipe then narrows down to a diameter of 2.0 cm.

jasenka [17]

Answer:

$P_{1}-P_{2}=12675Pa$

Explanation:

From the equation of continuity we know that:

$v_{1}A_{1}=v_{2}A_{2}\\Given \\r_{1}=2.0cm\\r_{2}=1.0cm\\v_{1}=1.3m/s\\Density of water p=1000kg/m^{3}\\Now\\A_{1}=\pi r_{1}^{2} \\A_{2}=\pi r_{2}^{2}\\ Therefore\\v_{2}=v_{1}\frac{A_{1}}{A_{2}}\\v_{2}=v_{1}\frac{\pi r_{1}^{2} }{\pi r_{2}^{2}}\\v_{2}=v_{1}\frac{r_{1}^{2} }{r_{2}^{2}}\\v_{2}=1.3*\frac{2.0^{2} }{1.0^{2} } \\v_{2}=5.2m/s\\$

From Bernoulli equation we know that:

$P_{1}+1/2pv_{1}^{2}+pgy_{1}=P_{2}+1/2pv_{2}^{2}+pgy_{2}\\$

Now assuming $y_{1}=y_{2}$

$P_{1}+(1/2)pv_{1}^{2}=P_{2}+(1/2)pv_{2}^{2}\\ P_{1}-P_{2}=1/2pv_{2}^{2} -1/2pv_{1}^{2}\\ P_{1}-P_{2}=1/2p(v_{2}^{2}-v_{1}^{2} )\\ P_{1}-P_{2}=1/2*1000(5.2^{2}-1.3^{2} )\\ P_{1}-P_{2}=12675Pa$

5 0

3 years ago

Maria is filling a bucket of water from a faucet. After she turns it on, she sees that the cross-sectional area of the water str

GenaCL600 [577]

Answer:

t = 47.62 sec

Explanation:

Given data;

$A_1 = 4.62 \times 10^4 m^2$

$A_2 = 2.52 \times 10^4 m^2$

h = 2.50 cm

volume 10 L

from

$A_1 v_1 = A_2 v_2$

$4.62 \times 10^4 v_1 = 2.52 \times 10^4 v_2$

$4.62 v_1 = 2.52 v_2$ ......1

from bernoulli eq

$P_1 + \frac{1}{2} \rho v_1^2 + \rho g h = P_2 + \frac{1}{2} \rho v_2^2$

$P_1 =P_2 = P_{atm}$

$v_2^2 = v_1^2 +2gh$ ... 2

from 1 and 2 equation

$v_1 = 0.46 m/s$

volume flow rate is

$Q = A_1 \times v_1 = 4.62 \times 10^[-4} v_1 = 2.1 \times 10^{-4} m^3/s$

$t = \frac{v}{Q}$

$t =\frac{10\times 10^{-3}}{2.1 \times 10^{-4}} = 47.62 s$

3 0

3 years ago

Read 2 more answers

The tendency of a stationary object to resist being put into motion is known as _______?

seropon [69]

Inertia. It also is the tendency of an object in motion to stay in motion in one specific direction.

5 0

4 years ago

A damped harmonic oscillator consists of a mass on a spring, with a small damping force that is proportional to the speed of the

exis [7]

Answer:

2.19 N/m

Explanation:

A damped harmonic oscillator is formed by a mass in the spring, and it does a harmonic simple movement. The period of it is the time that it does one cycle, and it can be calculated by:

T = 2π√(m/K)

Where T is the period, m is the mass (in kg), and K is the damping constant. So:

2.4 = 2π√(0.320/K)

√(0.320/K) = 2.4/2π

√(0.320/K) = 0.38197

(√(0.320/K))² = (0.38197)²

0.320/K = 0.1459

K = 2.19 N/m

4 0

3 years ago

A 3.0-kilogram mass is traveling in a circle of

dmitriy555 [2]

Answer:

$a=20\ m/s^2$

Explanation:

Given that,

The mass of an object, m = 3 kg

The radius of a circle, r = 0.2 m

The speed of the object, v = 2 m/s

We need to find the centripetal acceleration. Its formula is given by :

$a=\dfrac{v^2}{r}\\\\a=\dfrac{(2)^2}{0.2}\\\\a=20\ m/s^2$

So, the centripetal acceleration is $20\ m/s^2$ .

4 0

3 years ago