Answer:
Since 1997: A second is a time equal to 9,192,631,770 periods of radiation corresponding to the transition between two hyperfine levels of the ground state of the cesium-133 atom.
This definition refers to a caesium atom at rest at a temperature of 0 K
Explanation:
Answer:
Explanation: As the earthworm passes through the slime tube, the tube will pass over the female pore picking up eggs. The tube will continue to move down the earthworm and pass over the male pore called the spermatheca which has the stored sperm called the spermatozoa.
Answer
given,
mass of bowling ball = 7.25 Kg
moving speed of the bowling ball = 9.85 m/s
mass of bowling in = 0.875 Kg
scattered at an angle = θ = 21.5°
speed after the collision = 10.5 m/s
angle of the bowling ball
![tan \theta_1 = \dfrac{-[m_2v_2Sin \theta_2]}{m_1v_1 - (m_2v_2cos \theta_2)}](https://tex.z-dn.net/?f=tan%20%5Ctheta_1%20%3D%20%5Cdfrac%7B-%5Bm_2v_2Sin%20%5Ctheta_2%5D%7D%7Bm_1v_1%20-%20%28m_2v_2cos%20%5Ctheta_2%29%7D)
![tan \theta_1 = \dfrac{-[0.875\times 10.5 \times Sin 21.5^0]}{7.25\times 9.85 - (0.875\times 10.5 \times cos 21.5^0)}](https://tex.z-dn.net/?f=tan%20%5Ctheta_1%20%3D%20%5Cdfrac%7B-%5B0.875%5Ctimes%2010.5%20%5Ctimes%20Sin%2021.5%5E0%5D%7D%7B7.25%5Ctimes%209.85%20-%20%280.875%5Ctimes%2010.5%20%5Ctimes%20cos%2021.5%5E0%29%7D)
![tan \theta_1 = \dfrac{-[3.3672]}{62.86}](https://tex.z-dn.net/?f=tan%20%5Ctheta_1%20%3D%20%5Cdfrac%7B-%5B3.3672%5D%7D%7B62.86%7D)
b) magnitude of final velocity
v = 8.68 m/s
Answer:
The three major parts of a cell are:
a. Cell membrane
b. Nucleus
c. Cytoplasm
Explanation:
a. Cell membrane:
It provides protection for a cell.
b. Nucleus:
It controls and regulates the activities of cell.
c. Cytoplasm:
It supports and suspends organelles and cellular molecules.
The effiency of a machine is
(output work or energy) / (input work or energy) .
For the system described in the question, that's
(123 J) / (150 J) = 0.82 = 82% .
