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4 years ago

What happens when a negatively charged object A is brought near a neutral object B?

Physics

2 answers:

Mnenie [13.5K]4 years ago

7 0

What are the answer choices?

klemol [59]4 years ago

3 0

Explanation: Negatively charged particles will repel over negatively chargesparticles, and attract positively charges particles. ... As the negatively charged object approaches the neutral object, it will repel the electrons in the neutral object, creating an area of positive and negative overall charge.

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Suppose a 96.10 kg hiker has ascended to a height of 1841 m above sea level in the process of climbing Mt. Washington. By what p

lbvjy [14]

Answer:

0.029%

Explanation:

Weight on the surface is given by,

$F_W = mg = (96.1Kg)(9.8m/s^2)=941.78N$

The acceleration due to gravity at given height is,

$g_h=\frac{gR^2}{R+h^2}$

The weight in another height is equal to

$F_h=mg_h$

$F_h= m*\frac{gR^2}{R+h^2}$

$F_h = \frac{F_WR^2}{(R+h)^2}$

$F_h=\frac{(941.78)(6.371*10^6)}{(6.371*10^6+1841)}$

$F_h = 941.50N$

The change of the Weight is,

$\frac{F-F_h}{F}*100=\frac{941.78-941.50}{941.78}*100=0.029\%$

6 0

3 years ago

Suppose you calculated the speed of light in an unknown substance to be 4.00x10^8 m/s. How could you tell if you made an error i

Mice21 [21]

Answer: You could tell if you made an error in your calculations by repeating the steps.

Speed of light is the fastest/maximum in vacuum which is equal to 3 × 10^8 m/s, therefore speed of light through any material equal to 4 × 10^8 m/s is physically and theoretically impossible and therefore incorrect.

Explanation:

6 0

2 years ago

*photo attached* The diameters of the main rotor and tail rotor of a single-engine helicopter are 7.67 m and 1.01 m, respectivel

stiks02 [169]

(a) The speeds of the tips of both rotors; main rotor 178.3 m/s and tail rotor 218.4 m/s.

(b) The speed of the main rotor is 0.52 speed of sound, and the speed of the tail rotor is 0.64 speed of sound.

<h3>Linear speed of main motor and tail rotor</h3>

v = ωr

where;

ω is the angular speed (rad/s)
r is radius (m)

v(main rotor) = (444 rev/min x 2π rad x 1 min/60s) x (0.5 x 7.67 m)

v(main rotor) = 178.3 m/s

v(tail rotor) = (4,130 rev/min x 2π rad x 1 min/60s) x (0.5 x 1.01 m)

v(tail rotor) = 218.4 m/s

<h3>Speed of the rotors with respect to speed of sound</h3>

% speed (main motor) = 178.3/343 = 0.52 = 52 %

% speed (tail motor) = 218.4/343 = 0.64 = 64 %

Thus, the speed of the main rotor is 0.52 speed of sound, and the speed of the tail rotor is 0.64 speed of sound.

Learn more about linear speed here: brainly.com/question/15154527

#SPJ1

5 0

2 years ago

How many revolutions per minute would a 25 m -diameter ferris wheel need to make for the passengers to feel "weightless" at the

kozerog [31]

Refer to the diagram shown below.

Let ω = the angular velocity (rad/s) of the wheel.

At the topmost point, the passenger, with mass m, will feel weightless if the passenger's weight matches the centripetal force.
The passenger's weight is mg.
The centripetal force is mω²r.

Therefore
mω²r = mg
ω = √(g/r)

Because g = 9.8 m/s² and r = 25/2 = 12.5 m, therefore
ω = √(9.8/12.5) = 0.8854 rad/s

Because 1 revolution per second is 2π rad/s, therefore
$\omega = (0.8854 \, \frac{rad}{s} )*( \frac{1}{2 \pi} \, \frac{rev}{rad} )*(60 \, \frac{s}{min} ) = 8.455 \, rev/min$

Answer: 8.455 rev/min

8 0

3 years ago

A 5000 kg truck traveling at 60 m/s stops in 5 seconds. How much friction was between the truck's tires and the ground?

oksano4ka [1.4K]

Answer:

60000N

Explanation:

acceleration is change in velocity

a =(v-u)/t where a is acceleration u is initial velocity and v is final velocity

a = (0-60)/5 = -60/5= - 12m/s^2

here minus sign shows that body is decelerating and force is force of friction Now f = ma here f is force of friction m is mass and a is acceleration

f= 5000×- 12= -60000N

MINUS SIGN HERE SHOWS FORCE OF FRICTION

Hence force of friction is 60000N

8 0

4 years ago