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Svetradugi [14.3K]
3 years ago
11

Explain why the air we breathe and solids, such as steel and bronze, are solutions or homogeneous mixtures, just like salt water

is ?
Physics
2 answers:
eimsori [14]3 years ago
7 0

Answer:

Explanation:

There are two major types of mixtures; homogeneous and heterogeneous mixtures.

Homogeneous mixture is a mixture in which its constituent particles are evenly distributed throughout the mixture. Examples are steel, bronze and air (as stated in the question). While heterogeneous mixture is a mixture in which it's constituent particles are not evenly distributed throughout the mixture. Example includes sand and water solution.

Salt water is an homogeneous mixture because the percentage of salt in a sample of salt from a particular mixture is the same in every other sample (of the same volume) of the same mixture.

From the above, we can deduce that air is an homogeneous mixture because a sample of air (in a particular area) will contain the same constituent by proportion as another sample of air (in the same area). This means that the percentage of oxygen, nitrogen, carbon dioxide, water vapour, argon and other substances in one sample of the air will be equal to the percentage of this constituents in the other sample of the air.

Same can be said about steel and bronze. For steel, each gram of the same steel will contain the same percentage of carbon and iron. And also, each gram of the same bronze will contain the same percentage of copper, tin and other metals present.

For better understanding, let's consider an heterogeneous mixture. A mixture of sand and water solution cannot have the same proportion throughout, this is because sand particles in some samples (of a particular volume) of a particular mixture will be different from sand particles in some other samples (of the same volume) of the same mixture.

svet-max [94.6K]3 years ago
3 0
Because you can't physically see the difference.
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Sergio039 [100]

Answer:

The net power needed to change the speed of the vehicle is 275,000 W

Explanation:

Given;

mass of the sport vehicle, m = 1600 kg

initial velocity of the vehicle, u = 15 m/s

final velocity of the vehicle, v = 40 m/s

time of motion, t = 4 s

The force needed to change the speed of the sport vehicle;

F = \frac{m(v-u)}{t} \\\\F = \frac{1600(40-15)}{4} \\\\F = 10,000 \ N

The net power needed to change the speed of the vehicle is calculated as;

P_{net} = \frac{1}{2} F[u + v]\\\\P_{net} = \frac{1}{2} \times 10,000[15 + 40]\\\\P_{net} = 275,000 \ W

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A tiger travels 3m/s^2 for 4.1s,what was its initial speed if it's final speed was 55k/h?
zaharov [31]
Acceleration a=3m/s^2
time t= 4.1seconds
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initial velocity U= ?
First convert V to m/s
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A cylinder 0.170 m in diameter rotates in a lathe at 530 rpm . what is the tangential speed of the surface of the cylinder?
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Diameter = 0.170 meter
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A thin cylindrical shell and a solid cylinder have the same mass and radius. The two are released side by side and roll down, wi
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Answer:

Explanation:

Let the velocity be v

Total energy at the bottom

= rotational + linear kinetic energy

= 1/2 Iω² + 1/2 mv² ( I moment of inertia of shell  = mr² )

= 1/2 mr²ω² + 1/2 mv² ( v = ω r )

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