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Svetradugi [14.3K]
3 years ago
11

Explain why the air we breathe and solids, such as steel and bronze, are solutions or homogeneous mixtures, just like salt water

is ?
Physics
2 answers:
eimsori [14]3 years ago
7 0

Answer:

Explanation:

There are two major types of mixtures; homogeneous and heterogeneous mixtures.

Homogeneous mixture is a mixture in which its constituent particles are evenly distributed throughout the mixture. Examples are steel, bronze and air (as stated in the question). While heterogeneous mixture is a mixture in which it's constituent particles are not evenly distributed throughout the mixture. Example includes sand and water solution.

Salt water is an homogeneous mixture because the percentage of salt in a sample of salt from a particular mixture is the same in every other sample (of the same volume) of the same mixture.

From the above, we can deduce that air is an homogeneous mixture because a sample of air (in a particular area) will contain the same constituent by proportion as another sample of air (in the same area). This means that the percentage of oxygen, nitrogen, carbon dioxide, water vapour, argon and other substances in one sample of the air will be equal to the percentage of this constituents in the other sample of the air.

Same can be said about steel and bronze. For steel, each gram of the same steel will contain the same percentage of carbon and iron. And also, each gram of the same bronze will contain the same percentage of copper, tin and other metals present.

For better understanding, let's consider an heterogeneous mixture. A mixture of sand and water solution cannot have the same proportion throughout, this is because sand particles in some samples (of a particular volume) of a particular mixture will be different from sand particles in some other samples (of the same volume) of the same mixture.

svet-max [94.6K]3 years ago
3 0
Because you can't physically see the difference.
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The nucleus of an atom consists of neutrons and electrons. tf
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True because the neutrons are inside of the nucleus and the electron revolve around the nucleus
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3 years ago
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If you weighed 100 lb on Earth, what would you weigh at the upper atmosphere of Jupiter? For reference, Jupiter has a mass that
nignag [31]

Answer:

The answer to the question is

A 100 lb person would weigh 300.33 lbf at the upper atmosphere of Jupiter

Explanation:

To solve the question we note that

Mass of object = 100 lb =‪ 45.35924‬ kg

Mass of Jupiter = 300×Mass of Earth = 300×5.972 × 10²⁴ kg =1.7916×10²⁷ kg

Radius of Jupiter = 10× Radius of Earth = 10×6,371 km = 63710 km

Gravitational constant, G = 6.67408 × 10⁻¹¹ m³ kg-1 s-2

Gravitational force is given by F_G= \frac{Gm_1m_2}{r^2}

Plugging in the values we get

F_G = \frac{6.67408*10^{-11}*45.35924*1.7916*10^{27}}{63710^2} = 1335.93 N

Converting into lbf gives 1335.93 N *0.2248 lbf/N = 300.33 lbf

7 0
3 years ago
A string or rope will break apart if it is placed under too much tensile stress. Thicker ropes can withstand more tension withou
Lemur [1.5K]

Answer: The answer is 13.02 meter

Explanation: your question is incomplete, the complete question is this if A string or rope will break apart if it is placed under too much tensile stress. Thicker ropes can withstand more tension without breaking because the thicker the rope, the greater the cross-sectional area and the smaller the stress. One type of steel has a density of

7750kg/m3 and will break if the tensile stress exceeds 7.0×108N/m2.

You want to make a guitar string from a mass of 4.5 g of this type of steel. In use, the guitar string must be able to withstand a tension of 900 N without breaking. Your job is the following.

(a) Determine the maximum length the string can have

Answer:

As we know that density(p)= mass(m)/volume(V)

Solve for volume(V)= mass/density

If the given mass value is in gram then we have to divide it by 1000 to get the value in kilogram so our mass in kg will be 3.7/1000= 0.0037 kg

And if density is in kg/m^3

Then volume will be V= 0.0037/7730 =>

4.79^10-7m^3

Now we know that stress = Force/Area

For Area = force/stress => 900/7*10^8=> 2795.95m^2

For length= volume/Area => 4.79^10-7/2795.95

Length= 13.02 m

4 0
3 years ago
while working out a man performed 2525j of work in 19seconds . what was his power A:132.9w. B:241.5w C 47.975w. D100.5w
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A: 132.9w because 2525\19 is how much energy transferred per second which is also known as the power
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How much heat is required to convert 5.53 g of ice at -12.0 ∘C to water at 24.0 ∘C? (The heat capacity of ice is 2.09 J/(g⋅∘C),
fredd [130]

Answer:

2.55 × 10³ J =2.55 kJ

Explanation:

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Specific heat capacity of water = 76.0 J/ mol °C

Ice at -12 °C is converted to ice at 0 °C by absorbing heat Q₁

Ice at 0°C melts to water at 0 °C. Let Heat  absorbed during this phase change be Q₂ .

Let heat  absorbed to raise the temperature of water from 0 C to 24°C be Q₃ .

Total heat = Q = Q₁ + Q₂ + Q₃

Q₁ = (37.8 j/mol C )(5.53 g /18.01532 g/ mol )( 0-(-12)) = 139.23749 j

Q₂ =(5.53 g/18.01532 g H₂O / mol ) (6.02 x10³ j) = 1847.905 j

Q₃ = (76 j/mol C) ( (5.53 g/18.01532 g H₂O / mol )(24-0) = 559.8968 j

Total Heat required = Q = 139.23749 j + 1847.905 j + 559.8968 j

= 2547.039 j = 2.55 × 10³ J =2.55 kJ

5 0
3 years ago
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