Answer:
- large: 40 lbs
- small: 20 lbs
Step-by-step explanation:
A system of equations can be written for the weights of the boxes based on the relationships given in the problem statement. One equation will be for the total weight of 1 large and 1 small box; the other will be for the total weight of 70 large and 60 small boxes.
Let L and S represent the weights of Large and Small boxes, respectively. The system of equations is ...
L + S = 60 . . . . . . combined weight is 60 lbs
70L +60S = 4000 . . . . weight of boxes in the truck
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We can solve this by substituting for s in the second equation.
70L +60(60 -L) = 4000
10L = 400 . . . . . . . . . subtract 3600, simplify
L = 40
S = 60 -L = 20
A large box weighs 40 pounds; a small box weighs 20 pounds.
$ 1850 was invested in 9% account
<u>Solution:</u>
Given that
Total amount invested by man in two saving accounts = $9493
Simple interest on one account =9%
Simple interest on second account = 10%
Total interest earned = $930.80
Need to determine amount invested in 9 % account.
Let assume amount invested in account where Simple Interest is 9% = x
And assume amount invested in account where Simple Interest is 10% = y
As total amount invested in two accounts is $9493
=> x + y = 9493
=> y = 9493 - x ------(1)


As total interest earned = $930.80

On substituting value of y from equation(1) in above equation , we get
9x + 10 (9493 – x) = 93080
=> 9x + 94930 – 10x = 93080
=> -x = 93080 – 94930
=> -x = -1850
=> x = 1850
Amount invested in account where Simple Interest is 9% = x = $1850
Hence $1850 was invested in 9% account.
Alright so I'm coming up with this on the fly; you have the first six letters (a,b,c,d,e,f) and 0-9 and your ten numbers. calculate the amount of possible combinations for the letters by simply writing them down.
ab, ac, ad, ae, a f- five
bc, bd , be, bf- four
cd, ce, cf- three
de, df- two
ef,- one.
adding these all together gets a total of 15 for the letters. now the numbers
01, 02, 03, 04, 05, 06, 07, 08, 09- nine
12, 13, 14, 15, 16, 17, 18, 19- eight
23, 24, 25, 26, 27, 28, 29- seven
34, 35, 36, 37, 38, 39- six
45, 46, 47, 48, 49- five
56, 57, 58, 59- four
67, 68, 69- three
78, 79- two
89- one
added together with a total of 45 combinations.
alright so, 45 different number combinations and 15 letter combinations. multiplying 15 by 45 should tell you the total possible combinations for a two letter and two number serial-number
The fraction 22/7 has a value of 3.142857, so it has the same first three digits as pi. Both 3.14 and 22/7 are approximations of pi. In fact, 22/7 is close to pi than 3.14 is. Pi is irrational. That is, the decimal expansion never ends and never repeats, so any number of decimal places we wrote out is an approximation. The approximation 3.14 is about 1/2 percent off from the true value, and the fairly well know 3.141559 is within 0.000084 percent.