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Liono4ka [1.6K]
1 year ago
9

Is the pH greater than, equal to, or less than 7 after the neutralization of each of the following pairs of acids and bases? -NH

3 and HClO4 -NaOH and benzoic acid -KOH and HBr -(CH3)3N and HOBr
Chemistry
1 answer:
never [62]1 year ago
5 0

A strong electrolyte dissociates completely into its ions but in weak electrolyte only certain number of ions are dissociated so pH depends upon the dissociated ions.

Definition of pH

An evaluation of how basic a substance or solution is its pH is determined. pH is measured on a scale from 0 to 14. A pH value of 7 is considered to be neutral on this scale, which implies it is neither acidic nor basic. If the pH value is less than 7, it is considered to be acidic and if the pH value is greater than 7, it is considered to be basic.

pH < 7 for NH₃ and HClO₄ since the acid is strong acid and the base is weak base.

The pH value for NaOH and Benzoic acid is pH > 7, since the base is strong base and acid is a weak acid .

pH = 7 for HBr and KOH since both are strong acid and strong base

pH < 7 or pH > 7 since both are neutral.

Learn more about acids and bases from the given link given below.

brainly.com/question/28382743

#SPJ4

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Can someone help me and fast
jasenka [17]

Answer:

It is likely B.

Explanation:

8 0
3 years ago
Assume that a point mutation changes the codon AUU to AUC. Why is this a neutral mutation
lukranit [14]
I used the genetic code table. mRNA codon ===> amino acid

1st base       2nd base           3rd base
A                       U                             U               ===> Isoleucine
A                       U                             C               ===> Isoleucine

The point mutation of codon AUU to AUC is a neutral mutation because it neither benefits nor deter the ability of the organism to survive and reproduce.

As you can see, Both codons result to the Isoleucine amino acid.

Another codon that will still result to the Isoleucin amino acid is AUA.

3 0
3 years ago
you are running a transformation reaction, and in your microfuge tube currently is your plasmid and your insert fragments (both
ElenaW [278]

A foreign DNA molecule can be incorporated into a bacterial plasmid during a transformation reaction.

<h3>How to explain the reaction?</h3>

With the aid of two enzymes, ligase and restriction enzymes, a foreign DNA molecule can be incorporated into a bacterial plasmid during a transformation reaction. Each enzyme detects a target DNA sequence and cuts it nearby, while ligase aids in connecting the DNA. When two bits of DNA have complimentary bases, it facilitates their joining.

Plasmid and the insert fragment are both present in the microfuge tube, and they both have compatible sticky ends. However, the ligase has been denatured and is no longer active because the prior student left it outside rather than freezing it; despite this, we had already put the ligase into the tube. Ligase aids in binding the plasmid and insert fragments together, but because it is denatured in this instance, it will no longer be able to do so. As a result, no transformation process will take place. And since ligase links DNA fragments together by catalyzing the development of connections between the nearby nucleotides, the two fragments will not be able to unite.

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4 0
2 years ago
How many grams are there in 2.3*10^24 atoms of silver nitrate ?​
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2.3*10^24 atoms

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6 0
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ddd [48]
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