How many grams of CO2 would be made from 3.0 g of C6H6? Please no links
1 answer:
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The concentrations : 0.15 M
pH=11.21
<h3>Further explanation</h3>The ionization of ammonia in water :
NH₃+H₂O⇒NH₄OH
NH₃+H₂O⇒NH₄⁺ + OH⁻
The concentrations of all species present in the solution = 0.15 M
Kb=1.8 x 10⁻⁵
M=0.15
Answer:
Mass percentage of gold : 33.35%
Mass percentage of silver: 62.80%
Mass percentage of copper : 3.85%
Explanation:
Where : N = Number of atoms
n = moles
= Avogadro number
Let the total atoms present in the alloy be 100.
Atom percentage of silver = 44.9%
Atoms of of silver = 44.9% of 100 atoms = 44.9
Atomic weight of silver = 107.87 g/mol
Mass of 44.9 silver atoms = 107.87 g/mol × 44.9 = 4,843.363 g/mol
Atom percentage of gold= 46.3%
Atoms of of gold = 46.3% of 100 atoms = 46.3
Atomic weight of gold = 196.97 g/mol
Mass of 44.9 gold atoms = 196.97 g/mol × 46.3 = 9,119.711 g/mol
Atom percentage of copper = 8.8 %
Atoms of of copper = 8.8% of 100 atoms = 8.8
Atomic weight of copper = 63.55 g/mol
Mass of 44.9 copper atoms = 63.55 g/mol × 8.8 = 559.24 g/mol
Total mass of an alloy :4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol
Mass percentage of gold :
Mass percentage of silver:
Mass percentage of copper :