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makkiz [27]
3 years ago
13

How many grams of CO2 would be made from 3.0 g of C6H6? Please no links

Chemistry
1 answer:
g100num [7]3 years ago
3 0

Answer:

enter this link www.dontjointhislink.com

Just kidding..

You need to post the reaction equation to find it. Do you have it by any chance??

Explanation:

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How did uranium become present in Earth's upper crust? Choose one: A. It was delivered by comets that crashed into Earth's surfa
Luda [366]

Answer:

<em>Option A. It was delivered by comets that crashed into Earth's surface.</em>

Explanation:        

<em><u>Uranium (U) is a chemical element with atomic number 92.</u></em>        

<em />

<em>For many years, a large number of scientists have been studying the abundance and origin of the isotopes of uranium in Earth</em>. <u>According to some theories, the Earth's uranium was produced in one or more supernovae</u> (an explosive brightening of a star), in wich, the main process consists in the rapid capture of neutrons by seed nuclei at great rates. <u>Another theory proposes that uranium is created during the merger of two neutron stars</u> (neutron stars are very dense), because, when such dense bodies come closer together the gravitational force cause them to merge, producing huge amounts of hevy metals like uranium.                  

<u><em>Many analyses have been made of the uranium in rocks of the Earth. These measurements shows that the abundance of uranium is bigger in the crust and upper mantle of the Earth</em></u>.    

So, knowing that Earth's uranium was produced through one of these processes, <u><em>the best answer is option A, the uranium was delivered by comets that crashed into Earth's surface.</em></u>    

Have a nice day!                            

5 0
3 years ago
HELP! Give the molar mass of Copper (II) Hydroxide.
yarga [219]

Answer:

97.561 g/mol

Explanation:

8 0
2 years ago
g A solution contains 100mM NaCl, 20mM CaCl2, and 20mM urea. We would say this solution is __________ compared to a 300 mOsM sol
ICE Princess25 [194]

Answer:

A solution contains 100mM NaCl, 20mM CaCl2, and 20mM urea. We would say this solution is hypotonic compared to a 300 mOsM solution and hypotonic compared to a cell with 300 mOsM (non-penetrating solutes) interior.

Explanation:

The osmolarity is calculated from the molar concentration of the active particles in the solution. We have a solution that is composed of NaCl, CaCl₂ and urea.

When they are dissolved in water, they dissociate into particles as follows:

NaCl → Na⁺ + Cl⁻  (2 particles per compound)

CaCl₂ → Ca²⁺ + 2 Cl⁻ (3 particles per compound)

urea: not dissociation (1 particle per compound)

Then, we have to calculate the osmolarity of the solution. We multiply the molarity of each compound by the number of particles produced by the compound in water:

Osm = (100 mM NaCl x 2) + (20 mM CaCl₂ x 3) + (20 mM urea x 1) = 280 mOsm

Compared with 300 mOsm, 280 mOsm has a lower osmolarity, so it is a hypotonic solution.

To compare with a cell's osmolarity, we have to consider only the non-penetrating solutes. Urea is considered a penetrating solute for mammalian cells. So, the osmolarity of non-penetrating solutes (NaCl  and CaCl₂) is calculated as:

Osm (non-penetrating solutes) = (100 mM NaCl x 2) + (20 mM CaCl₂ x 3) = 260 mOsm

Therefore, we have:

Compared to 300 mOsm solution ⇒ 280 mOsm solution is a hypotonic solution

Compared to a cell with 300 mOsm ⇒ 260 mOsm solution is hypotonic

4 0
2 years ago
6 NaOH + 2 Al ???? 2 Na3AlO3 + 3 H2 How much aluminum is required to produce 17.5 grams of hydrogen? How many moles of NaOH are
ANTONII [103]

Answer:

a) 157.5 grams of aluminum.

b) 1 mol

c) 9 g

Explanation:

The reaction is :

6 NaOH + 2Al ---> 2 Na_{3}AlO_{3} + 3H_{2}

As per balanced equation

a) 3 moles of hydrogen will be produced from two moles of aluminium.

The atomic mass of aluminium = 27

therefore

3X2 grams of hydrogen is produced from 2 X 27 grams of Al

1 gram of hydrogen will be produced from \frac{2X27}{3X2}= 9g

therefore 17.5 will be produced from = 9X 17.5 = 157.5 grams of aluminum.

b) as per balanced equation three moles or six gram of hydrogen is produced from 6 moles of NaOH.

Therefore 1 g of hydrogen will be produced from =\frac{6}{6}

or 1 gram will be prepared from = 1 mole

c) from balanced equation three moles are produced from two moles of Al (27X2 = 54 g).

thus from 54  grams gives 6 grams of hydrogen

1 grams will give = \frac{54X1}{6}= 9 g

7 0
3 years ago
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It is known as a Solution
3 0
3 years ago
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