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3 years ago

Determine the identity of a cube of metal that measures 1.2 cm on each side and has a mass of 15.4g.

2 answers:

8 0

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density 15.4 grams per 1.2³ cm³ ≅ 8.9 grams per cm³
Find the metal that has a density of approximately 8.9 g/cm³

Sladkaya [172]3 years ago

4 0

Answer: The density of the cube of metal is $8.91g/cm^3$

Explanation:

To calculate the volume of cube, we use the formula:

$V=a^3$

where,

a = edge length of cube

Edge length of cube = 1.2 cm

Volume of cube = $(1.2)^3=1.728cm^3$

To calculate density of a substance, we use the equation:

$\text{Density}=\frac{\text{Mass}}{\text{Volume}}$

We are given:

Mass of cube = 15.4 g

Volume of cube = $1.728cm^3$

Putting values in above equation, we get:

$\text{Density}=\frac{15.4g}{1.728cm^3}=8.91g/cm^3$

Hence, the density of the cube of metal is $8.91g/cm^3$

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4 years ago

The vapor pressure of liquid acetone, CH3COCH3, is 100 mm Hg at 281 K. A 6.06E-2 g sample of liquid CH3COCH3 is placed in a clos

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Explanation:

According to ideal gas equation, product of pressure and volume equals the product of number of moles, gas constant and temperature.

Mathematically, PV = nRT

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T = temperature

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Hence, number of moles of given sample of acetone are as follows.

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= $\frac{6.06 \times 10^{-2}}{58 g/mol}$

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Therefore, putting the values in ideal gas equation as follows.

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In 1 atm equal to 760 mm Hg. So, convert 0.359 atm into mm Hg as follows.

$0.359 atm \times \frac{760 mm Hg}{1 atm}$

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4 years ago

Prepare 15 mg/dl working standard solution from a stock solution of 20 mg/dl. State the volume of diluent and dilution.

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Preparing 15 mg/gl working standard solution from a 20 mg/dl stock solution will require the application of the dilution principle.

Recalling the principle:

initial volume x initial molarity = final volume x final molarity

Since we were not given any volume to work with, we can as well just take an arbitrary volume to be prepared. Let's assume that the stock solution is 10 mL and we want to prepare 15 mg/gl from it:

Applying the dilution principle:

10 x 20 = final volume x 15

final volume = 200/15

= 13.33 mL

This means that in order to prepare 13.33 mL, 15 mg/l working standard solution from 10 ml, 20 mg/dl stock solution, 3.33 mL of the diluent must be added to the stock solution.

More on dilution principle can be found here: brainly.com/question/11493179

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3 years ago

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tekilochka [14]

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