Balance the following equations and write the corresponding ionic and net ionic equations (if appropriate):

Identify the correct charge of each atomic particle

MA_775_DIABLO [31]

Answer: The correct answer is Option B.

Explanation:

There are 3 sub-atomic particles present in an atom. They are: Electrons, protons and neutrons.

Electrons: They are negatively charged particles and are present around the nucleus in the orbits.
Protons: They are positively charged particles and are present inside the nucleus of an atom.
Neutrons: They are neutral particles which means they do not carry any charge. They are present in the nucleus of an atom.

Hence, the correct answer is Option B.

7 0

3 years ago

Read 2 more answers

Draw the lewis structure for the polyatomic trisulfide s−23 anion. be sure to include all resonance structures that satisfy the

mezya [45]

The following are the steps involved in drawing Lewis structure of the polyatomic trisulfide anion $S_{3}^{2-}$ :

Total number of valence electrons = $(3 * 6) + 2 = 20 electrons$

Resonance is not possible in this ion. The molecular geometry of the ion will be bent as there are two lone pairs and two bond pairs on the central atom.

3 0

3 years ago

ose you has aniline as your unknown. What kind of solid derivative would be suitable to synthesize for aniline

gayaneshka [121]

Answer:

Amides are suitable to synthesize aniline

Explanation:

Amide are basically used to synthesize aniline.

The chemical formula of Aniline is C6H5NH2 while that of Amide is RCONH2

Amide are solids that can be easily converted to amines.

4 0

2 years ago

A chemist heats the block of copper as shown in the interactive, then places the metal sample in a cup of oil at 25.00 °C instea

Mazyrski [523]

When the oil is added to the heated copper, the energy in the system is

conserved.

The mass of the oil in the cup, is approximately 64.73 grams.

Reasons:

The question parameters are;

Temperature of the oil in the cup = 25.00°C

Final temperature of the oil and copper, T₂ = 27.33 °C

Specific heat of copper, c₂ = 0.387 J/(g·°C)

Specific heat capacity of oil, c₁ = 1.74 J/(g·°C)

Required:

The mass of oil in the cup.

Solution:

The mass of the copper, m₂ = 17.920 g

Temperature of copper after heating, T₂ = 65.17°C

Temperature of the copper after being placed in the cup of oil, T₂ = 27.33°C

Heat lost by copper = Heat gained by the oil

m₂·c₂·(T₂ - T₃) = m₁·c₁·(T₃ - T₁)

Therefore, we get;

17.920 × 0.387 × (65.17 - 27.33) = m₁ × 1.74 × (27.33 - 25)

262.4219136 = 4.0542·m₁

m₁ ≈ 64.73

The mass of the oil in the cup, m₁ ≈ 64.73 g

Learn more here:

brainly.com/question/21406849

Possible part of the question obtained from a similar question online, are;

The mass of the copper, m₂ = 17.920 g

Temperature of copper after heating = 65.17°C

6 0

3 years ago

Calculate the pH of a solution with an H+ ion concentration of 9.36 x 10-3 M ?

mel-nik [20]

Answer:

The answer is 2.03

Explanation:

The pH of a solution can be found by using the formula

$pH = - log [ {H}^{+} ]$

where H+ is the Hydrogen ion concentration

From the question we have

$pH = - log(9.36 \times {10}^{ - 3} ) \\ = 2.02872415...$

We have the final answer as

Hope this helps you

6 0

2 years ago