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3 years ago

The value of y is directly proportional to the value of x.

Mathematics

2 answers:

Paladinen [302]3 years ago

7 0

Answer:

a) find the value of y when x is equal to 4.

Step-by-step explanation:

creativ13 [48]3 years ago

7 0

Answer:

a) the value of y will be x=5 - 4= 1

therefore y=1

b) the value of x will be y= 10 - 6= 4

therefore x=4

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A lighthouse casts a 128-ft shadow. A nearby lamppost that measures 5

Yakvenalex [24]

Answer:

80 ft

Step-by-step explanation:

Let the height of the light house be x feet.

$\therefore \: \frac{128}{8} = \frac{x}{5} \\ \\ x = \frac{128 \times 5}{8} \\ \\ x = \frac{640}{8} \\ \\ x = 80 \: feet$

5 0

3 years ago

2)<br> 8xy -- 3y + 2 ( 9x - 5y + 4 ) if x = 3, y = - 4

Scilla [17]

Answer:

8xy-3y + 2(9x-5y+4) = 18

Step-by-step explanation:

We need to find the value of the given expression:

8xy-3y + 2(9x-5y+4) ....(1)

when x = 3 and y = -4

Put the values of a and y in equation (1)

8×3×(-4)-3(-4)+ 2(9×3-5(-4)+4)

= -96 +12 + 2(27 + 20 +4)

= -84 + 2(51)

= -84 + 102

= 18

Hence, the value of the given expression is 18.

4 0

3 years ago

The populations P (in thousands) of a certain city from 2000 through 2007 can be modeled by P = 1674.7e^kt, where t represents t

Makovka662 [10]

Answer:

k = 0.02278

Step-by-step explanation:

Given that:

The population P = 1674.7e^kt

where;

t represents the year,

if year 2000 represents t = 0

Then, the year 2007 represents = 7; &

year 2006 represents = 6

In 2006, population recorded in the city was about 1,920 thousand

Therefore;

$1920 = 1674.7e^{(k\times 6)$

Taking the logarithm of both sides, we get:

$\mathtt{ In}(1920) = \mathtt{ In} ( 1674.7)+ 6k$

7.560080465= 7.423389324 + 6k

7.560080465 - 7.423389324 = 6k

0.136691141 = 6k

k = 0.136691141/6

k ≅ 0.02278

5 0

3 years ago

Help, please and than

Papessa [141]

Answer:

$3\frac{11}{18}$

Step-by-step explanation:

6 0

3 years ago

Quadrilateral ABCD is translated to get quadrilateral A'B'C'D'. vertex A is at (-5,2) , and vertex A' is ay (2,-2), quadrilatera

belka [17]

Answer:

(-1,3)

Step-by-step explanation:

Given that the quadrilateral ABCD is translated to get quadrilateral A'B'C'D'. The vertex A is at (-5,2) is translated to vertex A' is at (2,-2).

The translation is x-direction, a, is the difference of x-coordinates of both the points, a=2-(-5)=2+5=7.

The translation is y-direction, b, is the difference of y-coordinates of both the points, b = -2-2 = -4.

As all the points are translated by the same magnitude as well as in the same direction, so by adding a to x and b to y coordinate of any points, the translated point can be determined.

The vertex of point B is (-6,5), so, the vertex of the point B' would be (-6+a, 5+b)=(-6+7, 5+(-4))=(-1,3).

Hence, the vertex of point B' is (-1,3).

5 0

3 years ago