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vivado [14]
4 years ago
12

Which of the following describes the electron sharing between hydrogen and fluorine A.Hydrogen and fluorine share one electron w

ith each other B.
Hydrogen and fluorine share seven electrons with each other C.Hydrogen shares seven electrons, while fluorine shares one electron. D.Hydrogen shares one electron, while fluorine shares seven electrons
Physics
1 answer:
atroni [7]4 years ago
5 0
Hydrogen has one electron in its outermost shell, while fluorine has seven electron in its outermost shell, hence both hydrogen and fluorine needs a single electron to complete its outermost shell. 
That's why there is a single bond between hydrogen and fluorine.
Hence both hydrogen and fluorine share one electron with each other, so option "A" is correct.
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A wave is traveling through a string and six waves pass a point in three seconds what is the frequency of the wave
Butoxors [25]

Frequency of the wave is 2 per second

Explanation:

  • Frequency is the number of times waves pass at a particular point of time. Here, given time period = 3 s and number of waves that pass in 3 seconds = 6. Find the frequency of the wave per second.
  • Frequency is given by the formula

f = 1/T, where f is the frequency and T is the time period

  • For 3 seconds, frequency is 6

3 seconds ⇒ 6 waves

⇒ 1 second = 6/3 = 2 waves per second

8 0
3 years ago
g PRACTICE ANOTHER Two trains approach each other on separate but adjacent tracks. Train 1 is traveling at a speed of 30.3 m/s a
e-lub [12.9K]

Answer:

  f'= 607.8 Hz

Explanation:

This is a Doppler effect exercise due to the relative velocity of the sound source and the observer.

By the time the source and the observer are getting closer the expression is

         f ’=f_o \ \frac{ v+ v_o}{v - v_s}

where vs is the speed of the source, vo is the speed of the observer, if the bodies move away the signs are exchanged

in this case, train 1 emits sound, so its speed is v_s = 30.3 m / s and train 2 is the receiver of the sound v₀ = 22.5 m / s

let's calculate

          f ’= 520 \ ( \frac{343 + 22.5}{343 - 30.3} )520 (343+ 22.5 / 343 - 30.3)

          f'= 607.8 Hz

6 0
3 years ago
Why are all machines not 100% efficient<br> A. Mass<br> B. Gravity <br> C. Friction <br> D. Distance
Anon25 [30]
All machines are not 100% efficient because of <span>C. Friction</span>
7 0
4 years ago
Read 2 more answers
Which statement best describes the similarities between fundamental forces? a Electromagnetic and strong nuclear forces influenc
MrRissso [65]

Answer:

a

Explanation:

............

..............option A

6 0
3 years ago
Read 2 more answers
A laser beam is incident on two slits with a separation of 0.230 mm, and a screen is placed 4.75 m from the slits. If the bright
Mariulka [41]

Answer:

7.55\times 10^{-7} m

Explanation:

We are given that

d=0.23 mm=0.23\times 10^{-3} m

1mm=10^{-3} m

Screen is placed  from the slits at distance ,L=4.75 m

The bright interference fringes on the screen are separated  by 1.56 cm.

\Delta y=1.56 cm=1.56\times 10^{-2} m

1 m=100 cm

We have to find the wavelength of laser light.

We know that

\Delta y=\frac{\lambda L}{d}

Substitute the values

1.56\times 10^{-2}=\frac{\lambda\times 4.75}{0.23\times 10^{-3}}

\lambda=\frac{1.56\times 10^{-2}\times 0.23\times 10^{-3}}{4.75}

\lambda=7.55\times 10^{-7} m

4 0
3 years ago
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