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olasank [31]
3 years ago
7

An airplane accelerates down a runway at 3 m/s2 for 32 s until is finally lifts off the ground. Determine the distance traveled

before takeoff.
Physics
1 answer:
Alex Ar [27]3 years ago
4 0

Answer:

12 or 24

Explanation:

i think it is i hope it is right

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Two massive, positively charged particles are initially held a fixed distance apart. When they are moved farther apart, the magn
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c. n

The magnitude of the gravitational force is given by Newton's law of universal gravitation:

F_g=-G\frac{m_1m_2}{d^2}

Here G is the gravitational constant, m_1, m_2 are the masses of the particles and d is the distance between them.

The magnitude of the electrostatic force is given by Coulomb's law:

F_e=k\frac{q_1q_2}{d^2}

Here k is the Coulomb constant, q_1, q_2 are the chargues of the particles and d is the distance between them.

As can be seen, both forces are inversely proportional to the square of the distance. Thus, the factor is the same in both cases.

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How do you build a sticky piston door​
Pani-rosa [81]

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it can be built in mine craft

Explanation:

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If we relied solely on the nonrenewable resources found in the U.S., which one would we run out of first at current usage levels
lisabon 2012 [21]

If we are depending on nonrenewable resources only then we will run out first at that resource which we are using at large level

that resource which is used at all levels at very fast level but we can't get it at that rate from natural sources

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a car has a mass of 200kg. It is on a hill 1000m high. How much gravitational potential energy does the car have?
wariber [46]

Answer:

Explanation:

PE = m * g * h

m = 200 kg

h = 1000 m

g = 9.81

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PE = 1962000 Joules

7 0
3 years ago
5. How far can a car travel in 14 hours while going at a speed of 75 miles per hour?
Gemiola [76]

\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

Speed of the car is 75 miles per hour and it travels for 14 hours. so the distance travelled by it in the given period of time can be calculated using this formula ~

\qquad \sf  \dashrightarrow \: d = v \sdot t

\qquad \sf  \dashrightarrow \: d = 75 \times 14

\qquad \sf  \dashrightarrow \: d = 1050 \:  \: miles

so, it can travel 1050 miles in 14 hours

5 0
2 years ago
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