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goblinko [34]
3 years ago
9

I need help with my SS quiz

Physics
1 answer:
ki77a [65]3 years ago
6 0
What’s the question?
You might be interested in
V=xf-xi/t solve for t
irina [24]

Answer:

t=\frac{x_f-x_i}{v}

Explanation:

Starting from the equation:

v=\frac{x_f-x_i}{t}

First of all, let's multiply by t on both sides:

v\cdot t = \frac{x_f-x_i}{t}\cdot t \\vt = x_f - x_i

And then, let's divide by v on both sides:

\frac{vt}{v}=\frac{x_f-x_i}{v}\\t=\frac{x_f-x_i}{v}

So, finally

t=\frac{x_f-x_i}{v}

7 0
3 years ago
Why is detergent mixed in a toothpaste?
babymother [125]

because detergent has to clean dirt outa clothes and tooth pste also can help get stains outa cloths and when you put those two mixtures tofgether it can make the ultimate cleaning mixture

8 0
3 years ago
A 5.00 gram bullet moving at 600 m/s penetrates a tree trunk to a depth of 4.00 cm.
Crazy boy [7]
A) Work energy relation;
 Work =ΔKE ; work done = Force × distance, while, Kinetic energy = 1/2 MV²
 F.s = 1/2mv²
F× 4×10^-2 = 1/2 × 5 ×10^-3 × (600)²
 F = 900/0.04
    = 22500 N
Therefore, force is 22500 N

b) From newton's second law of motion;
 F = Ma
Thus; a = F/m
             = 22500/(5×10^-3)
             = 4,500,000 m/s²
But v = u-at
  0 = 600- 4500,000 t
t = 1.33 × 10^-4 seconds
6 0
4 years ago
A potter's wheel has the shape of a solid uniform disk of mass 13.0 kg and radius 1.25 m. It spins about an axis perpendicular t
Fittoniya [83]

Answer:10.82 kg-m^2

Explanation:

Given

Mass of solid uniform disk M=13 kg

radius of disk r=1.25 m

mass of lump m=1.7 kg

distance of lump from axis r_0=0.63

Moment of inertia is the distribution of mass from the axis of rotation

Initial moment of inertia of disk I_1=\frac{Mr^2}{2}

I_1=\frac{13\times 1.25^2}{2}=10.15 kg-m^2

Final moment of inertia I_f=Moment of inertia of disk+moment of inertia of lump about axis

I_f=\frac{Mr^2}{2}+mr_0^2

I_f=10.15+1.7\times 0.63^2

I_f=10.15+0.674

I_f=10.82 kg-m^2

3 0
4 years ago
A boat with a horizontal tow rope pulls a waterskier. She skis off to the side, the rope makes an angle of 15° with the forward
dsp73

Answer:

<h3>13,976.23Joules</h3>

Explanation:

Workdone by the rope is expressed using the formula;

W = Fd sin(theta)

F is the tension in the rope = 180

d is the displacement = 300m

theta is the angle of inclination = 15°

Substitute the given parameters into the formula;

W = 180(300)sin15

W = 54000sin 15

W = 13,976.23

Hence the workdone by the rope is 13,976.23Joules

4 0
3 years ago
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