Answer:

Explanation:
Starting from the equation:

First of all, let's multiply by t on both sides:

And then, let's divide by v on both sides:

So, finally

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A) Work energy relation;
Work =ΔKE ; work done = Force × distance, while, Kinetic energy = 1/2 MV²
F.s = 1/2mv²
F× 4×10^-2 = 1/2 × 5 ×10^-3 × (600)²
F = 900/0.04
= 22500 N
Therefore, force is 22500 N
b) From newton's second law of motion;
F = Ma
Thus; a = F/m
= 22500/(5×10^-3)
= 4,500,000 m/s²
But v = u-at
0 = 600- 4500,000 t
t = 1.33 × 10^-4 seconds
Answer:
Explanation:
Given
Mass of solid uniform disk 
radius of disk 
mass of lump 
distance of lump from axis 
Moment of inertia is the distribution of mass from the axis of rotation
Initial moment of inertia of disk 

Final moment of inertia
=Moment of inertia of disk+moment of inertia of lump about axis




Answer:
<h3>13,976.23Joules</h3>
Explanation:
Workdone by the rope is expressed using the formula;
W = Fd sin(theta)
F is the tension in the rope = 180
d is the displacement = 300m
theta is the angle of inclination = 15°
Substitute the given parameters into the formula;
W = 180(300)sin15
W = 54000sin 15
W = 13,976.23
Hence the workdone by the rope is 13,976.23Joules