Given:
It is given that,
PQ ⊥ PS and
∠QPR = 7x-9
∠RPS = 4x+22
To find the value of ∠QPR.
Formula
As per the given problem PR lies between PQ and PS,
So,
∠QPR+∠RPS = 90°
Now,
Putting the values of ∠RPS and ∠QPR we get,
or, 
or, 
or, 
or, 
Substituting the value of in ∠QPR we get,
∠QPR = 
or, ∠QPR = 
Hence,
The value of ∠QPR is 40°.
Answer:
x=2
Step-by-step explanation:
logx (2x)^3 = 6
We can rewrite without the exponent
3 logx (2x) = 6
Divide by 3
3/3 logx (2x) = 6/3
logx (2x) = 2
Raise each side to the base x
x^ logx (2x) =x^ 2
2x = x^2
Subtract 2x from each side
2x-2x = x^2 -2x
0 = x^2 -2x
Factor an x
0 = x(x-2)
Using the zero product property
x =0 x-2 =0
x =0 x=2
We cannot have a base of 0, so x cannot equal 0
x=2
Answer:
45/63
Step-by-step explanation:
6 3/10=63/10, 4 1/2=45/10,
(45/10)/(63/10)=45/63
Answer:
32
Step-by-step explanation:
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